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This suggested edit was approved and applied to the post over 3 years ago by MissMulan‭.

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  • When 2 inductors share the same magnetic field they become coupled and besides their self inductance they have a mutual inductance as well.
  • For this circuit:
  • ![](https://electrical.codidact.com/uploads/9BbSeaQgDrCoxDMhzybYnxP9)
  • Now current entering one coil marked with a dot , produces a current exitting the couple coil at its dotting end.In L1 current enters from the dotted end so this creates a current which exits from the dotted end of L2 and in L2 current enters from the dotted end so this again creates a current which exits from the dotted end of L1 so we get 2 voltage drops from self inductance of each coil and 2 voltage drops from the mutual inductance of the coupled coils.
  • ![I](https://electrical.codidact.com/uploads/9rF1TGmSbyjXheyYbaf81p3z)
  • so that is translated to this equation:
  • ![](https://electrical.codidact.com/uploads/emSsaAC41ngoDAQM1JsoPyNq)
  • Now obviously :
  • ![](https://electrical.codidact.com/uploads/UGnT3PZrtT6aqkMHLrsnwmdq)
  • The total inductance of the circuit becomes ![](https://electrical.codidact.com/uploads/vdsK3wj6wSQYEpeKCPvXCnpv)
  • the value of the mutual inductance is:(with k=1)
  • ![](https://electrical.codidact.com/uploads/X3znhTfjLipcUBHdWcQUfpv4)
  • $L_{T}=4H$
  • and the equation of current of this circuit becomes
  • ![](https://electrical.codidact.com/uploads/6q6XKefrqD8ZUzYHqmJNcKox)
  • When 2 inductors share the same magnetic field they become coupled and besides their self inductance they have a mutual inductance as well.
  • For this circuit:
  • ![](https://electrical.codidact.com/uploads/9BbSeaQgDrCoxDMhzybYnxP9)
  • Now current entering one coil marked with a dot, produces a current exiting the couple coil at its dotting end. In L1 current enters from the dotted end so this creates a current which exits from the dotted end of L2 and in L2 current enters from the dotted end so this again creates a current which exits from the dotted end of L1 so we get 2 voltage drops from self inductance of each coil and 2 voltage drops from the mutual inductance of the coupled coils.
  • ![I](https://electrical.codidact.com/uploads/9rF1TGmSbyjXheyYbaf81p3z)
  • so that is translated to this equation:
  • ![](https://electrical.codidact.com/uploads/emSsaAC41ngoDAQM1JsoPyNq)
  • Now obviously :
  • ![](https://electrical.codidact.com/uploads/UGnT3PZrtT6aqkMHLrsnwmdq)
  • The total inductance of the circuit becomes ![](https://electrical.codidact.com/uploads/vdsK3wj6wSQYEpeKCPvXCnpv)
  • the value of the mutual inductance is: (with k=1)
  • ![](https://electrical.codidact.com/uploads/X3znhTfjLipcUBHdWcQUfpv4)
  • $L_{T}=4 \text{H}$
  • and the equation of current of this circuit becomes
  • ![](https://electrical.codidact.com/uploads/6q6XKefrqD8ZUzYHqmJNcKox)

Suggested over 3 years ago by Elliot Alderson‭