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Comments on Duty cycle of buck-boost converter

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Duty cycle of buck-boost converter

+5
−1

I have the following problem: -

Image alt text

Using Wikipedia I find that during CCM we have the relation: -

$$\frac{V_{out}}{V_{in}} = -\frac{D}{1-D} $$

Solving for $D$ and inserting values gives me

$$D=\frac{20\text{V}}{20\text{V}-24\text{V}} = -5 $$

But this doesn't seem to make sense. First of all, the duty cycle is negative... Second the duty cycle is more than 100%!

Why do I get this erroneous result?

EDIT

Turns out I used the wrong formula. Using the formulas given by my instructor for the course: -

Image alt text

yields $d=0.454545 $

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1 comment thread

What I'm calculating is $$D=\frac{20\text{V}}{-24\text{V}-20\text{V}} = -0.45... $$ (1 comment)
What I'm calculating is $$D=\frac{20\text{V}}{-24\text{V}-20\text{V}} = -0.45... $$
DeadMouse‭ wrote over 2 years ago

What I'm calculating is

$$D=\frac{20\text{V}}{-24\text{V}-20\text{V}} = -0.45... $$