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When the outage occurred, I observed the following The L1/G voltage difference was 120V (good). The G/L2 voltage difference was 90V (bad). The L1/L2 voltage difference was 30V (very bad!). If t...
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#2: Post edited
- > When the outage occurred, I observed the following
- - The L1/G voltage difference was 120V (good).
- - The G/L2 voltage difference was 90V (bad).
- - The L1/L2 voltage difference was 30V (very bad!).
If the L2 wire was broken then, due to capacitive coupling between L1 and L2 (and the use of a high impedance voltmeter), the voltage on L2 will appear to be close in value and phase angle to L1. Hence you see a 30 volt difference between L1 and L2 and L2 is circa 90 volts above ground.Concusion: L2 is broken and naturally picks up a voltage die to capacitive coupling. I've seen this before.
- > When the outage occurred, I observed the following
- - The L1/G voltage difference was 120V (good).
- - The G/L2 voltage difference was 90V (bad).
- - The L1/L2 voltage difference was 30V (very bad!).
- If the L2 wire was broken then, due to capacitive coupling between L1 and L2 (and the use of a high impedance voltmeter), the voltage on L2 will appear to be close in value to the L1 voltage. Hence you see a 30 volt difference between L1 and L2 and, L2 is circa 90 volts above ground.
- Concusion: L2 is broken and naturally picks up a voltage due to capacitive coupling. I've seen this before.
#1: Initial revision
> When the outage occurred, I observed the following - The L1/G voltage difference was 120V (good). - The G/L2 voltage difference was 90V (bad). - The L1/L2 voltage difference was 30V (very bad!). If the L2 wire was broken then, due to capacitive coupling between L1 and L2 (and the use of a high impedance voltmeter), the voltage on L2 will appear to be close in value and phase angle to L1. Hence you see a 30 volt difference between L1 and L2 and L2 is circa 90 volts above ground. Concusion: L2 is broken and naturally picks up a voltage die to capacitive coupling. I've seen this before.