Post History
I answer to myself because I believe this subject is interesting and not very well understood, even to professionals. Also, I want to point out that this answer is the product of my own investigati...
Answer
#4: Post edited
by
Lorenzo Donati
·
2023-08-11T12:02:49Z (over 1 year ago)
Corrected use of "non-standard" (hence unclear) abbreviation for operational amplifier.
- I answer to myself because I believe this subject is interesting and not very well understood, even to professionals. Also, I want to point out that this answer is the product of my own investigations and simulations, and is not coming from reliable sources or knowledge.
- First of all, I want to point out that the bootstrapping technique is mainly used in the context of transistor based amplifiers, mainly BJT.
- In the following image, R1, Rc, RE and R2 form the usual topology of a BJT amplifier. The bootstrap is formed by resistor R3 and cap "Cboot":
- 
- In this context, the bootstrap technique is alive and well! Excellent related questions and answers can be found [here](https://electronics.stackexchange.com/questions/268944/effect-of-bootstrapping-in-amplifier-circuit).
I will not enter into this matter since it is well known and the original question is related to oamp bootstrapping.- I only point out that the main point is that the bootstrapping technique avoids the loading of the AC signal by the biasing resistors.
Now, let me return to the main question: oamp bootstrapping.- Despite what the "Art of electronics" says (and also, to some respect, what Olin said above), this technique, if correctly understood, can be still useful in some circumstances.
- Here is the main point of bootstrapping: often, an AC signal needs to be passed through a cap, and then buffered or amplified.
- There may be several reasons to pass the input signal through a cap, the most obvious one being you want to annihilate some DC bias present in the input signal.
- Doing so, it is mandatory to follow immediately the cap with a resistor called "a return path to ground". Here is an illustration of what is meant:
- 
Without a return path to ground, the output of the oamp would be undefined: for example, if there is no input signal at all, you expect that the output of the oamp be 0. But without a return path, the oamp would charge cap C, and its output would stabilize somewhere between its supply voltages, most often near Vcc+ or Vcc-. Usually, the return path R has to be chosen in such a way that the RC time constant is well below the lowest frequency of interest present inside the input signal.- This being said, for very very sensitive input signals, even a return path of 10 Mega ohm may load the signal heavily: it may be necessary to make the return path to ground at least 1Gohm or more, which is not convenient. This is where the bootstrap technique may be useful (see schematic inside the question): it virtually annihilates the the return path at the AC level, and ensures the signal loading is minimal, that is, no more than the input current of the amplifier.
- A last question remains: what values should be chosen for the resistors R1=R2=R and C in the schematics of the question.
- Well, this is again function of the RC time constant. More precisely, the cut off frequency 1/2πRC has to be chosen well below the lowest frequency of interest present in the signal. For example, R = 1 Mega ohm and C = 100 nF fits most signals > 10Hz.
- To sum up:
* The oamp bootstrap technique is used to prevent the return path to ground to load the input signal;- * It can be advantageously used for extremely sensitive input signals to ensure the signal is loaded as few a possible, that is, no more than the input current of the amplifier itself;
* Hence, it allows using standard resistor (in the range of 1 M ohm), and in fact oamps with higher input current, since they surely works with return path of 1 M ohm.- * Perhaps most importantly, this technique allows not worrying about the value of the return path to ground: it ensures the circuit
- works in the optimal way anyway.
- * finally, regarding what values to choose for the resistor and the bootstrap cap, it appears that R = 1 Mega ohm and C = 100 nF works in most of the cases, whenever the frequency of the AC signal is > 10Hz.
- I answer to myself because I believe this subject is interesting and not very well understood, even to professionals. Also, I want to point out that this answer is the product of my own investigations and simulations, and is not coming from reliable sources or knowledge.
- First of all, I want to point out that the bootstrapping technique is mainly used in the context of transistor based amplifiers, mainly BJT.
- In the following image, R1, Rc, RE and R2 form the usual topology of a BJT amplifier. The bootstrap is formed by resistor R3 and cap "Cboot":
- 
- In this context, the bootstrap technique is alive and well! Excellent related questions and answers can be found [here](https://electronics.stackexchange.com/questions/268944/effect-of-bootstrapping-in-amplifier-circuit).
- I will not enter into this matter since it is well known and the original question is related to opamp bootstrapping.
- I only point out that the main point is that the bootstrapping technique avoids the loading of the AC signal by the biasing resistors.
- Now, let me return to the main question: opamp bootstrapping.
- Despite what the "Art of electronics" says (and also, to some respect, what Olin said above), this technique, if correctly understood, can be still useful in some circumstances.
- Here is the main point of bootstrapping: often, an AC signal needs to be passed through a cap, and then buffered or amplified.
- There may be several reasons to pass the input signal through a cap, the most obvious one being you want to annihilate some DC bias present in the input signal.
- Doing so, it is mandatory to follow immediately the cap with a resistor called "a return path to ground". Here is an illustration of what is meant:
- 
- Without a return path to ground, the output of the opamp would be undefined: for example, if there is no input signal at all, you expect that the output of the opamp be 0. But without a return path, the opamp would charge cap C, and its output would stabilize somewhere between its supply voltages, most often near Vcc+ or Vcc-. Usually, the return path R has to be chosen in such a way that the RC time constant is well below the lowest frequency of interest present inside the input signal.
- This being said, for very very sensitive input signals, even a return path of 10 Mega ohm may load the signal heavily: it may be necessary to make the return path to ground at least 1Gohm or more, which is not convenient. This is where the bootstrap technique may be useful (see schematic inside the question): it virtually annihilates the the return path at the AC level, and ensures the signal loading is minimal, that is, no more than the input current of the amplifier.
- A last question remains: what values should be chosen for the resistors R1=R2=R and C in the schematics of the question.
- Well, this is again function of the RC time constant. More precisely, the cut off frequency 1/2πRC has to be chosen well below the lowest frequency of interest present in the signal. For example, R = 1 Mega ohm and C = 100 nF fits most signals > 10Hz.
- To sum up:
- * The opamp bootstrap technique is used to prevent the return path to ground to load the input signal;
- * It can be advantageously used for extremely sensitive input signals to ensure the signal is loaded as few a possible, that is, no more than the input current of the amplifier itself;
- * Hence, it allows using standard resistor (in the range of 1 M ohm), and in fact opamps with higher input current, since they surely works with return path of 1 M ohm.
- * Perhaps most importantly, this technique allows not worrying about the value of the return path to ground: it ensures the circuit
- works in the optimal way anyway.
- * finally, regarding what values to choose for the resistor and the bootstrap cap, it appears that R = 1 Mega ohm and C = 100 nF works in most of the cases, whenever the frequency of the AC signal is > 10Hz.
#3: Post edited
by
coquelicot
·
2020-10-04T10:48:13Z (about 4 years ago)
- I answer to myself because I believe this subject is interesting and not very well understood, even to professionals. Also, I want to point out that this answer is the product of my own investigations and simulations, and is not coming from reliable sources or knowledge.
- First of all, I want to point out that the bootstrapping technique is mainly used in the context of transistor based amplifiers, mainly BJT.
- In the following image, R1, Rc, RE and R2 form the usual topology of a BJT amplifier. The bootstrap is formed by resistor R3 and cap "Cboot":
- 
- In this context, the bootstrap technique is alive and well! Excellent related questions and answers can be found [here](https://electronics.stackexchange.com/questions/268944/effect-of-bootstrapping-in-amplifier-circuit).
- I will not enter into this matter since it is well known and the original question is related to oamp bootstrapping.
- I only point out that the main point is that the bootstrapping technique avoids the loading of the AC signal by the biasing resistors.
- Now, let me return to the main question: oamp bootstrapping.
- Despite what the "Art of electronics" says (and also, to some respect, what Olin said above), this technique, if correctly understood, can be still useful in some circumstances.
Here is the main point of bootstrapping: often, and AC signal needs to be passed through a cap, and then buffered or amplified.- There may be several reasons to pass the input signal through a cap, the most obvious one being you want to annihilate some DC bias present in the input signal.
- Doing so, it is mandatory to follow immediately the cap with a resistor called "a return path to ground". Here is an illustration of what is meant:
- 
- Without a return path to ground, the output of the oamp would be undefined: for example, if there is no input signal at all, you expect that the output of the oamp be 0. But without a return path, the oamp would charge cap C, and its output would stabilize somewhere between its supply voltages, most often near Vcc+ or Vcc-. Usually, the return path R has to be chosen in such a way that the RC time constant is well below the lowest frequency of interest present inside the input signal.
- This being said, for very very sensitive input signals, even a return path of 10 Mega ohm may load the signal heavily: it may be necessary to make the return path to ground at least 1Gohm or more, which is not convenient. This is where the bootstrap technique may be useful (see schematic inside the question): it virtually annihilates the the return path at the AC level, and ensures the signal loading is minimal, that is, no more than the input current of the amplifier.
- A last question remains: what values should be chosen for the resistors R1=R2=R and C in the schematics of the question.
- Well, this is again function of the RC time constant. More precisely, the cut off frequency 1/2πRC has to be chosen well below the lowest frequency of interest present in the signal. For example, R = 1 Mega ohm and C = 100 nF fits most signals > 10Hz.
- To sum up:
- * The oamp bootstrap technique is used to prevent the return path to ground to load the input signal;
- * It can be advantageously used for extremely sensitive input signals to ensure the signal is loaded as few a possible, that is, no more than the input current of the amplifier itself;
- * Hence, it allows using standard resistor (in the range of 1 M ohm), and in fact oamps with higher input current, since they surely works with return path of 1 M ohm.
- * Perhaps most importantly, this technique allows not worrying about the value of the return path to ground: it ensures the circuit
- works in the optimal way anyway.
- * finally, regarding what values to choose for the resistor and the bootstrap cap, it appears that R = 1 Mega ohm and C = 100 nF works in most of the cases, whenever the frequency of the AC signal is > 10Hz.
- I answer to myself because I believe this subject is interesting and not very well understood, even to professionals. Also, I want to point out that this answer is the product of my own investigations and simulations, and is not coming from reliable sources or knowledge.
- First of all, I want to point out that the bootstrapping technique is mainly used in the context of transistor based amplifiers, mainly BJT.
- In the following image, R1, Rc, RE and R2 form the usual topology of a BJT amplifier. The bootstrap is formed by resistor R3 and cap "Cboot":
- 
- In this context, the bootstrap technique is alive and well! Excellent related questions and answers can be found [here](https://electronics.stackexchange.com/questions/268944/effect-of-bootstrapping-in-amplifier-circuit).
- I will not enter into this matter since it is well known and the original question is related to oamp bootstrapping.
- I only point out that the main point is that the bootstrapping technique avoids the loading of the AC signal by the biasing resistors.
- Now, let me return to the main question: oamp bootstrapping.
- Despite what the "Art of electronics" says (and also, to some respect, what Olin said above), this technique, if correctly understood, can be still useful in some circumstances.
- Here is the main point of bootstrapping: often, an AC signal needs to be passed through a cap, and then buffered or amplified.
- There may be several reasons to pass the input signal through a cap, the most obvious one being you want to annihilate some DC bias present in the input signal.
- Doing so, it is mandatory to follow immediately the cap with a resistor called "a return path to ground". Here is an illustration of what is meant:
- 
- Without a return path to ground, the output of the oamp would be undefined: for example, if there is no input signal at all, you expect that the output of the oamp be 0. But without a return path, the oamp would charge cap C, and its output would stabilize somewhere between its supply voltages, most often near Vcc+ or Vcc-. Usually, the return path R has to be chosen in such a way that the RC time constant is well below the lowest frequency of interest present inside the input signal.
- This being said, for very very sensitive input signals, even a return path of 10 Mega ohm may load the signal heavily: it may be necessary to make the return path to ground at least 1Gohm or more, which is not convenient. This is where the bootstrap technique may be useful (see schematic inside the question): it virtually annihilates the the return path at the AC level, and ensures the signal loading is minimal, that is, no more than the input current of the amplifier.
- A last question remains: what values should be chosen for the resistors R1=R2=R and C in the schematics of the question.
- Well, this is again function of the RC time constant. More precisely, the cut off frequency 1/2πRC has to be chosen well below the lowest frequency of interest present in the signal. For example, R = 1 Mega ohm and C = 100 nF fits most signals > 10Hz.
- To sum up:
- * The oamp bootstrap technique is used to prevent the return path to ground to load the input signal;
- * It can be advantageously used for extremely sensitive input signals to ensure the signal is loaded as few a possible, that is, no more than the input current of the amplifier itself;
- * Hence, it allows using standard resistor (in the range of 1 M ohm), and in fact oamps with higher input current, since they surely works with return path of 1 M ohm.
- * Perhaps most importantly, this technique allows not worrying about the value of the return path to ground: it ensures the circuit
- works in the optimal way anyway.
- * finally, regarding what values to choose for the resistor and the bootstrap cap, it appears that R = 1 Mega ohm and C = 100 nF works in most of the cases, whenever the frequency of the AC signal is > 10Hz.
#2: Post edited
by
coquelicot
·
2020-10-04T10:46:14Z (about 4 years ago)
complete reediting, following the comment of Olin.
- I answer to myself because I believe this subject is interesting and not very well understood, even to professionals. Also, I want to point out that this answer is the product of my own investigations and simulations, and is not coming from reliable sources or knowledge.
- Despite what the "Art of electronics" says (and also, to some respect, what Olin said above), this technique, if correctly understood, can be still useful in some circumstances.
Here is the main point of bootstrapping: often, and AC signal needs to be passed through a cap, and then buffered or amplified. When doing so, it is mandatory to follow immediately the cap with a resistor called "a return path to ground":- 
Now, for very very sensitive input signals, even a return path of 10 Mega ohm may load the signal heavily: it may be necessary to make the return path to ground at least 1Gohm or more, which is not convenient. This is where the bootstrap technique may be useful: it virtually annihilate the the return path at the AC level, and ensures the signal loading is minimal, that is, no more than the input current of the amplifier.- To sum up:
* The bootstrap technique is used to prevent the return path to ground to load the input signal;* It can be advantageously used to ensure the signal is loaded as few a possible, that is, no more than the input current of the amplifier itself;- * Hence, it allows using standard resistor (in the range of 1 M ohm), and in fact oamps with higher input current, since they surely works with return path of 1 M ohm.
- * Perhaps most importantly, this technique allows not worrying about the value of the return path to ground: it ensures the circuit
- works in the optimal way anyway.
* finally, regarding what values to choose for the resistor and the bootstrap cap, it appears that R = 1 Mega ohm and C = 0.1 uF works in most of the cases, whenever the frequency of the AC signal is > 10Hz.
- I answer to myself because I believe this subject is interesting and not very well understood, even to professionals. Also, I want to point out that this answer is the product of my own investigations and simulations, and is not coming from reliable sources or knowledge.
- First of all, I want to point out that the bootstrapping technique is mainly used in the context of transistor based amplifiers, mainly BJT.
- In the following image, R1, Rc, RE and R2 form the usual topology of a BJT amplifier. The bootstrap is formed by resistor R3 and cap "Cboot":
- 
- In this context, the bootstrap technique is alive and well! Excellent related questions and answers can be found [here](https://electronics.stackexchange.com/questions/268944/effect-of-bootstrapping-in-amplifier-circuit).
- I will not enter into this matter since it is well known and the original question is related to oamp bootstrapping.
- I only point out that the main point is that the bootstrapping technique avoids the loading of the AC signal by the biasing resistors.
- Now, let me return to the main question: oamp bootstrapping.
- Despite what the "Art of electronics" says (and also, to some respect, what Olin said above), this technique, if correctly understood, can be still useful in some circumstances.
- Here is the main point of bootstrapping: often, and AC signal needs to be passed through a cap, and then buffered or amplified.
- There may be several reasons to pass the input signal through a cap, the most obvious one being you want to annihilate some DC bias present in the input signal.
- Doing so, it is mandatory to follow immediately the cap with a resistor called "a return path to ground". Here is an illustration of what is meant:
- 
- Without a return path to ground, the output of the oamp would be undefined: for example, if there is no input signal at all, you expect that the output of the oamp be 0. But without a return path, the oamp would charge cap C, and its output would stabilize somewhere between its supply voltages, most often near Vcc+ or Vcc-. Usually, the return path R has to be chosen in such a way that the RC time constant is well below the lowest frequency of interest present inside the input signal.
- This being said, for very very sensitive input signals, even a return path of 10 Mega ohm may load the signal heavily: it may be necessary to make the return path to ground at least 1Gohm or more, which is not convenient. This is where the bootstrap technique may be useful (see schematic inside the question): it virtually annihilates the the return path at the AC level, and ensures the signal loading is minimal, that is, no more than the input current of the amplifier.
- A last question remains: what values should be chosen for the resistors R1=R2=R and C in the schematics of the question.
- Well, this is again function of the RC time constant. More precisely, the cut off frequency 1/2πRC has to be chosen well below the lowest frequency of interest present in the signal. For example, R = 1 Mega ohm and C = 100 nF fits most signals > 10Hz.
- To sum up:
- * The oamp bootstrap technique is used to prevent the return path to ground to load the input signal;
- * It can be advantageously used for extremely sensitive input signals to ensure the signal is loaded as few a possible, that is, no more than the input current of the amplifier itself;
- * Hence, it allows using standard resistor (in the range of 1 M ohm), and in fact oamps with higher input current, since they surely works with return path of 1 M ohm.
- * Perhaps most importantly, this technique allows not worrying about the value of the return path to ground: it ensures the circuit
- works in the optimal way anyway.
- * finally, regarding what values to choose for the resistor and the bootstrap cap, it appears that R = 1 Mega ohm and C = 100 nF works in most of the cases, whenever the frequency of the AC signal is > 10Hz.
#1: Initial revision
by
coquelicot
·
2020-10-03T19:43:58Z (about 4 years ago)
I answer to myself because I believe this subject is interesting and not very well understood, even to professionals. Also, I want to point out that this answer is the product of my own investigations and simulations, and is not coming from reliable sources or knowledge. Despite what the "Art of electronics" says (and also, to some respect, what Olin said above), this technique, if correctly understood, can be still useful in some circumstances. Here is the main point of bootstrapping: often, and AC signal needs to be passed through a cap, and then buffered or amplified. When doing so, it is mandatory to follow immediately the cap with a resistor called "a return path to ground":  Now, for very very sensitive input signals, even a return path of 10 Mega ohm may load the signal heavily: it may be necessary to make the return path to ground at least 1Gohm or more, which is not convenient. This is where the bootstrap technique may be useful: it virtually annihilate the the return path at the AC level, and ensures the signal loading is minimal, that is, no more than the input current of the amplifier. To sum up: * The bootstrap technique is used to prevent the return path to ground to load the input signal; * It can be advantageously used to ensure the signal is loaded as few a possible, that is, no more than the input current of the amplifier itself; * Hence, it allows using standard resistor (in the range of 1 M ohm), and in fact oamps with higher input current, since they surely works with return path of 1 M ohm. * Perhaps most importantly, this technique allows not worrying about the value of the return path to ground: it ensures the circuit works in the optimal way anyway. * finally, regarding what values to choose for the resistor and the bootstrap cap, it appears that R = 1 Mega ohm and C = 0.1 uF works in most of the cases, whenever the frequency of the AC signal is > 10Hz.