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A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs. Based on this scheme the differential amplifier is substrac...
#10: Post edited
what is the role of the differential amplifier in a delta sigma converter?
- What is the role of the differential amplifier in a delta sigma converter?
A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs. so based on this scheme- 
- the differential amplifier is substracting an input with a delayed input and outputing a tiny difference to the integrator and that is confusing.
so as mentioned in the title how does the differential amplifier behave or whats it role?**Note:** am a beginner fascinated by electronics bear with me.
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs. Based on this scheme
- 
- the differential amplifier is substracting an input with a delayed input and outputing a tiny difference to the integrator and that is confusing.
- So as mentioned in the title, how does the differential amplifier behave or whats is its role?
- **Note:** am a beginner fascinated by electronics, bear with me.
#8: Post edited
what is the role of differential amplifier in a delta sigma converter?
- what is the role of the differential amplifier in a delta sigma converter?
#7: Post edited
differential amplifier in delta sigma converter
- what is the role of differential amplifier in a delta sigma converter?
A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputsVO = Ad (V1 - V2) **(ideal differential amplifier)**.The differential Gain (Ad = – (R3 / R1))CMRR = 20 logs (Ad / Ac)so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)**VO = Ad(V1 - V2)VO = 100(5.005-4.995)VO = 1 voltNow the questions:1. why do we need only the difference?2. in the delta-sigma converter, why substracting an input with a delayed input?3. why do we need a differential amplifier in the delta-sigma converter?Note: am a beginner fascinated by electronics. I did a lot of reading before I post my questions here so if my questions looks a little bit stupid bear with me and guide me that gonna be nice of you.**edite/update:**the questions were based on this scheme and other like it on internet
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs. so based on this scheme
- 
- the differential amplifier is substracting an input with a delayed input and outputing a tiny difference to the integrator and that is confusing.
- so as mentioned in the title how does the differential amplifier behave or whats it role?
- **Note:** am a beginner fascinated by electronics bear with me.
#5: Post edited
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs
- VO = Ad (V1 - V2) **(ideal differential amplifier)**.
- The differential Gain (Ad = – (R3 / R1))
- CMRR = 20 logs (Ad / Ac)
- 
- so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)**
- VO = Ad(V1 - V2)
- VO = 100(5.005-4.995)
- VO = 1 volt
- Now the questions:
- 1. why do we need only the difference?
- 2. in the delta-sigma converter, why substracting an input with a delayed input?
- 3. why do we need a differential amplifier in the delta-sigma converter?
- Note: am a beginner fascinated by electronics. I did a lot of reading before I post my questions here so if my questions looks a little bit stupid bear with me and guide me that gonna be nice of you.
- **edite/update:**
- the questions were based on this scheme and other like it on internet
- 
the updated schematic make more sense
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs
- VO = Ad (V1 - V2) **(ideal differential amplifier)**.
- The differential Gain (Ad = – (R3 / R1))
- CMRR = 20 logs (Ad / Ac)
- 
- so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)**
- VO = Ad(V1 - V2)
- VO = 100(5.005-4.995)
- VO = 1 volt
- Now the questions:
- 1. why do we need only the difference?
- 2. in the delta-sigma converter, why substracting an input with a delayed input?
- 3. why do we need a differential amplifier in the delta-sigma converter?
- Note: am a beginner fascinated by electronics. I did a lot of reading before I post my questions here so if my questions looks a little bit stupid bear with me and guide me that gonna be nice of you.
- **edite/update:**
- the questions were based on this scheme and other like it on internet
- 
#4: Post edited
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs
- VO = Ad (V1 - V2) **(ideal differential amplifier)**.
- The differential Gain (Ad = – (R3 / R1))
- CMRR = 20 logs (Ad / Ac)
- 
- so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)**
- VO = Ad(V1 - V2)
- VO = 100(5.005-4.995)
- VO = 1 volt
- Now the questions:
- 1. why do we need only the difference?
- 2. in the delta-sigma converter, why substracting an input with a delayed input?
- 3. why do we need a differential amplifier in the delta-sigma converter?
- Note: am a beginner fascinated by electronics. I did a lot of reading before I post my questions here so if my questions looks a little bit stupid bear with me and guide me that gonna be nice of you.
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs
- VO = Ad (V1 - V2) **(ideal differential amplifier)**.
- The differential Gain (Ad = – (R3 / R1))
- CMRR = 20 logs (Ad / Ac)
- 
- so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)**
- VO = Ad(V1 - V2)
- VO = 100(5.005-4.995)
- VO = 1 volt
- Now the questions:
- 1. why do we need only the difference?
- 2. in the delta-sigma converter, why substracting an input with a delayed input?
- 3. why do we need a differential amplifier in the delta-sigma converter?
- Note: am a beginner fascinated by electronics. I did a lot of reading before I post my questions here so if my questions looks a little bit stupid bear with me and guide me that gonna be nice of you.
- **edite/update:**
- the questions were based on this scheme and other like it on internet
- 
- the updated schematic make more sense
- 
#3: Post edited
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs
- VO = Ad (V1 - V2) **(ideal differential amplifier)**.
- The differential Gain (Ad = – (R3 / R1))
- CMRR = 20 logs (Ad / Ac)
- 
- so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)**
- VO = Ad(V1 - V2)
- VO = 100(5.005-4.995)
- VO = 1 volt
- Now the questions:
- 1. why do we need only the difference?
- 2. in the delta-sigma converter, why substracting an input with a delayed input?
- 3. why do we need a differential amplifier in the delta-sigma converter?
Note: am a beginner fascinated by electronics. I did a lot of reading before I post my questions here so if my questions look a little stupid bear with me and guide me that gonna be nice of you.
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs
- VO = Ad (V1 - V2) **(ideal differential amplifier)**.
- The differential Gain (Ad = – (R3 / R1))
- CMRR = 20 logs (Ad / Ac)
- 
- so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)**
- VO = Ad(V1 - V2)
- VO = 100(5.005-4.995)
- VO = 1 volt
- Now the questions:
- 1. why do we need only the difference?
- 2. in the delta-sigma converter, why substracting an input with a delayed input?
- 3. why do we need a differential amplifier in the delta-sigma converter?
- Note: am a beginner fascinated by electronics. I did a lot of reading before I post my questions here so if my questions looks a little bit stupid bear with me and guide me that gonna be nice of you.
#2: Post edited
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs
- VO = Ad (V1 - V2) **(ideal differential amplifier)**.
- The differential Gain (Ad = – (R3 / R1))
- CMRR = 20 logs (Ad / Ac)
- 
- so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)**
- VO = Ad(V1 - V2)
- VO = 100(5.005-4.995)
- VO = 1 volt
so now the questions:1. why we need only the difference?2. in the delta-sigma converter why we are substracting an input with an delayed input?3. why we need a differential amplifier in the delta-sigma converter?Note: am a beginner fascinated by electronics I did a lot of reading before I post my questions here so if my questions look a little stupid bear with me and guide me that gonna be nice of you.
- A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs
- VO = Ad (V1 - V2) **(ideal differential amplifier)**.
- The differential Gain (Ad = – (R3 / R1))
- CMRR = 20 logs (Ad / Ac)
- 
- so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)**
- VO = Ad(V1 - V2)
- VO = 100(5.005-4.995)
- VO = 1 volt
- Now the questions:
- 1. why do we need only the difference?
- 2. in the delta-sigma converter, why substracting an input with a delayed input?
- 3. why do we need a differential amplifier in the delta-sigma converter?
- Note: am a beginner fascinated by electronics. I did a lot of reading before I post my questions here so if my questions look a little stupid bear with me and guide me that gonna be nice of you.
#1: Initial revision
differential amplifier in delta sigma converter
A differential amplifier amplifies the difference between the two input voltages but suppresses any voltage common to the two inputs VO = Ad (V1 - V2) **(ideal differential amplifier)**. The differential Gain (Ad = – (R3 / R1)) CMRR = 20 logs (Ad / Ac)  so as an example: V1=5.005 V2=4.995 Ad=100 **(ideal opamp)** VO = Ad(V1 - V2) VO = 100(5.005-4.995) VO = 1 volt so now the questions: 1. why we need only the difference? 2. in the delta-sigma converter why we are substracting an input with an delayed input? 3. why we need a differential amplifier in the delta-sigma converter? Note: am a beginner fascinated by electronics I did a lot of reading before I post my questions here so if my questions look a little stupid bear with me and guide me that gonna be nice of you.