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Q&A Driving ADC with opamp with large rails

Here is a solution to protects very well the ADC from over-voltage spikes, avoid any simulation and design consideration, and that also protects the ADC from a possible negative output spike from t...

posted 4y ago by coquelicot‭  ·  edited 4y ago by coquelicot‭

Answer
#4: Post edited by user avatar coquelicot‭ · 2020-12-17T18:43:10Z (almost 4 years ago)
  • Here is a solution to protects very well the ADC from over-voltage spikes, avoid any simulation and design consideration, and that also protects the ADC from a possible negative output spike from the op-amp output at startup.
  • ![protect_ADC](https://electrical.codidact.com/uploads/pe8wFaG5m1nEYpKmgDje3KFW)
  • For high frequencies, it may be necessary to put a "compensation capacitor" as explained in the answer of Olin.
  • > Or just Shottky diodes to ground and the A/D supply. The Shottkys should kick in before the protection circuitry of the A/D. With a normal silicon junction drop, the internal protection circuitry might take most of the load.
  • The problem is that we know nothing about this ADC device. So, I consider it as a device sensitive to over-voltage, that may or may not have a protection circuitry against negative input voltage.
  • Now, if it has no protection, the zener, with its 0.6V forward voltage should be sufficient in most cases (otherwise a Schottky may be connected in parallel as suggested by Olin). But if the ADC device has a negative input voltage protection, then even if it takes most of the load, it will dissipate at most 15*15/300 = 0.75W. I can hardly imagine a protection circuitry that is not able to dissipate this power.
  • Here is a solution to protects very well the ADC from over-voltage spikes, avoid any simulation and design consideration, and that also protects the ADC from a possible negative output spike from the op-amp output at startup.
  • ![protect_ADC](https://electrical.codidact.com/uploads/pe8wFaG5m1nEYpKmgDje3KFW)
  • For high frequencies, it may be necessary to put a "compensation capacitor" as explained in the answer of Olin.
  • > Or just Shottky diodes to ground and the A/D supply. The Shottkys should kick in before the protection circuitry of the A/D. With a normal silicon junction drop, the internal protection circuitry might take most of the load.
  • The problem is that we know nothing about this ADC device. So, I consider it as a device sensitive to over-voltage, that may or may not have a protection circuitry against negative input voltage.
  • Now, if it has no protection, the zener, with its 0.6V forward voltage should be sufficient in most cases (otherwise a Schottky may be connected in parallel as suggested by Olin). But if the ADC device has a negative input voltage protection, then even if it takes most of the load, it will dissipate at most 0.6 * 15/300 = 0.03 W. I can hardly imagine a protection circuitry that is not able to dissipate this power.
#3: Post edited by user avatar coquelicot‭ · 2020-12-17T18:26:43Z (almost 4 years ago)
  • Here is a solution to protects very well the ADC from over-voltage spikes, avoid any simulation and design consideration, and that also protects the ADC from a possible negative output spike from the op-amp output at startup.
  • ![protect_ADC](https://electrical.codidact.com/uploads/pe8wFaG5m1nEYpKmgDje3KFW)
  • For high frequencies, it may be necessary to put a "compensation capacitor" as explained in the answer of Olin.
  • Here is a solution to protects very well the ADC from over-voltage spikes, avoid any simulation and design consideration, and that also protects the ADC from a possible negative output spike from the op-amp output at startup.
  • ![protect_ADC](https://electrical.codidact.com/uploads/pe8wFaG5m1nEYpKmgDje3KFW)
  • For high frequencies, it may be necessary to put a "compensation capacitor" as explained in the answer of Olin.
  • > Or just Shottky diodes to ground and the A/D supply. The Shottkys should kick in before the protection circuitry of the A/D. With a normal silicon junction drop, the internal protection circuitry might take most of the load.
  • The problem is that we know nothing about this ADC device. So, I consider it as a device sensitive to over-voltage, that may or may not have a protection circuitry against negative input voltage.
  • Now, if it has no protection, the zener, with its 0.6V forward voltage should be sufficient in most cases (otherwise a Schottky may be connected in parallel as suggested by Olin). But if the ADC device has a negative input voltage protection, then even if it takes most of the load, it will dissipate at most 15*15/300 = 0.75W. I can hardly imagine a protection circuitry that is not able to dissipate this power.
#2: Post edited by user avatar coquelicot‭ · 2020-12-17T17:33:10Z (almost 4 years ago)
  • Here is a solution to protects very well the ADC from over-voltage spikes, avoid any simulation and design consideration, and that also protects the ADC from a possible negative output spike from the op-amp output at startup.
  • ![protect_ADC](https://electrical.codidact.com/uploads/pe8wFaG5m1nEYpKmgDje3KFW)
  • Here is a solution to protects very well the ADC from over-voltage spikes, avoid any simulation and design consideration, and that also protects the ADC from a possible negative output spike from the op-amp output at startup.
  • ![protect_ADC](https://electrical.codidact.com/uploads/pe8wFaG5m1nEYpKmgDje3KFW)
  • For high frequencies, it may be necessary to put a "compensation capacitor" as explained in the answer of Olin.
#1: Initial revision by user avatar coquelicot‭ · 2020-12-17T17:20:39Z (almost 4 years ago)
Here is a solution to protects very well the ADC from over-voltage spikes, avoid any simulation and design consideration, and that also protects the ADC from a possible negative output spike from the op-amp output at startup.

![protect_ADC](https://electrical.codidact.com/uploads/pe8wFaG5m1nEYpKmgDje3KFW)