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Q&A Why are antenna PCB traces square instead of rounded?

Corners and chambers that are a small fraction of a wavelength are not significant in the <4Ghz band. More significant is the tolerance and loss tangent on the substrate. They would hardly be m...

posted 3y ago by TonyStewart‭  ·  edited 3y ago by TonyStewart‭

Answer
#3: Post edited by user avatar TonyStewart‭ · 2021-05-04T22:21:49Z (almost 3 years ago)
  • Corners and chambers that are a small fraction of a wavelength are not significant in the <4Ghz band. More significant is the tolerance and loss tangent on the substrate. They would hardly be measureable even with a 2 ps TDR.
  • WHAT COUNTS is the RL and loss tangent.
  • Corners and chambers that are a small fraction of a wavelength are not significant in the <4Ghz band. More significant is the tolerance and loss tangent on the substrate. They would hardly be measureable even with a 2 ps TDR. Emissions are not significantly different.
  • WHAT COUNTS is the RL and loss tangent.
#2: Post edited by user avatar TonyStewart‭ · 2021-05-04T22:21:10Z (almost 3 years ago)
  • Corners and chambers that are a small fraction of a wavelength are not significant in the <4Ghz band. More significant is the tolerance and loss tangent on the substrate. They would hardly be measureable even with a 2 ps TDR.
  • Corners and chambers that are a small fraction of a wavelength are not significant in the <4Ghz band. More significant is the tolerance and loss tangent on the substrate. They would hardly be measureable even with a 2 ps TDR.
  • WHAT COUNTS is the RL and loss tangent.
#1: Initial revision by user avatar TonyStewart‭ · 2021-05-04T22:20:40Z (almost 3 years ago)
Corners and chambers that are a small fraction of a wavelength are not significant in the <4Ghz band. More significant is the tolerance and loss tangent on the substrate. They would hardly be  measureable even with a 2 ps TDR.