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Q&A Help with differential to single ended voltage converter

Question: What is the purpose of the current mirror? Answer: It allows to combine the current changes in BOTH transistors (T1, T2). Explanation In a classical differential amplifier (with separat...

posted 3y ago by LvW‭  ·  edited 3y ago by LvW‭

Answer
#3: Post edited by user avatar LvW‭ · 2021-06-28T09:57:43Z (over 3 years ago)
  • **Question**: What is the purpose of the current mirror?
  • **Answer**: It allows to combine the current changes in BOTH transistors (T1, T2).
  • **Explanation** In a classical differential amplifier (with separate collector resistances for T1 and T2) we must use the difference between the collector voltages or currents for further prodessing - when we want to use the full dynamic capabilities of the amplifier.
  • This can be accomplished using the shown current mirror with simultaneous double-ended into single-ended conversion.
  • Resulting from a differential input signal the collector currents of T1 and T2 change their values in the opposite direction. However, the current mirror does not "allow" such a change because it tries to keep the currents equal.
  • Therefore, the difference is available as an **output current iout** which drives the next stage.
  • So we have:
  • ic1=ic3+2ib and ic2=-ic1=ic4+iout;
  • With ic4=ic3 this gives:
  • **iout=-2(ic1+ib)**
  • **Question**: What is the purpose of the current mirror?
  • **Answer**: It allows to combine the current changes in BOTH transistors (T1, T2).
  • **Explanation** In a classical differential amplifier (with separate collector resistances for T1 and T2) we must use the difference between the collector voltages or currents for further processing - when we want to use the full dynamic capabilities of the amplifier.
  • This can also be accomplished using the shown current mirror - with simultaneous double-ended into single-ended conversion.
  • Resulting from a differential input signal the collector currents of T1 and T2 change their values in the opposite direction. However, the current mirror does not "allow" such a change because it tries to keep the currents equal.
  • Therefore, the difference between the currents is available as an **output current iout** which drives the next stage, which makes the current-to-voltage conversion.
  • So we have:
  • ic1=ic3+2ib and ic2=-ic1=ic4+iout;
  • With ic4=ic3 this gives:
  • **iout=-2(ic1+ib)**
#2: Post edited by user avatar LvW‭ · 2021-06-28T08:43:07Z (over 3 years ago)
  • **Question**: What is the purpose of the current mirror?
  • Answer: It allows to combine the current changes in BOTH transistors (T1, T2).
  • **Answer:** In a classical differential amplifier (with separate collector resistances for T1 and T2) we must use the difference between the collector voltages or currents for further prodessing - when we want to use the full dynamic capabilities of the amplifier.
  • This can be accomplished using the shown current mirror with simultaneous double-ended into single-ended conversion.
  • **Explanation**: Resulting from a differential input signal the collector currents of T1 and T2 change their values in the opposite direction. However, the current mirror does not "allow" such a change because it tries to keep the currents equal.
  • Therefore, the difference is available as an **output current iout** which drives the next stage.
  • So we have:
  • ic1=ic3+2ib and ic2=-ic1=ic4+iout;
  • With ic4=ic3 this gives:
  • **iout=-2(ic1+ib)**
  • **Question**: What is the purpose of the current mirror?
  • **Answer**: It allows to combine the current changes in BOTH transistors (T1, T2).
  • **Explanation** In a classical differential amplifier (with separate collector resistances for T1 and T2) we must use the difference between the collector voltages or currents for further prodessing - when we want to use the full dynamic capabilities of the amplifier.
  • This can be accomplished using the shown current mirror with simultaneous double-ended into single-ended conversion.
  • Resulting from a differential input signal the collector currents of T1 and T2 change their values in the opposite direction. However, the current mirror does not "allow" such a change because it tries to keep the currents equal.
  • Therefore, the difference is available as an **output current iout** which drives the next stage.
  • So we have:
  • ic1=ic3+2ib and ic2=-ic1=ic4+iout;
  • With ic4=ic3 this gives:
  • **iout=-2(ic1+ib)**
#1: Initial revision by user avatar LvW‭ · 2021-06-28T08:40:55Z (over 3 years ago)
**Question**: What is the purpose of the current mirror?
Answer: It allows to combine the current changes in BOTH transistors (T1, T2). 

**Answer:** In a classical differential amplifier (with separate collector resistances for T1 and T2) we must use the difference between the collector voltages or currents for further prodessing - when we want to use the full dynamic capabilities of the amplifier.

This can be accomplished using the shown current mirror with simultaneous double-ended into single-ended conversion.

**Explanation**: Resulting from a differential input signal the collector currents of T1 and T2 change their values in the opposite direction. However, the current mirror does not "allow" such a change because it tries to keep the currents equal. 

Therefore, the difference is available as an **output current iout** which drives the next stage.

So we have:

ic1=ic3+2ib and ic2=-ic1=ic4+iout;

With ic4=ic3 this gives:
**iout=-2(ic1+ib)**