Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

Post History

33%
+0 −2
Q&A Voltage of tank circuit is invalid

In a previous question we found that for a critically damped oscillation: $$ I(t) = 2 t e^{-0.5 t} $$But if we integrate to find the voltage through the capacitor: $$ V_{CO} + \frac{1}{C} \cd...

1 answer  ·  posted 3y ago by MissMulan‭  ·  edited 9mo ago by Lorenzo Donati‭

#4: Post edited by user avatar Lorenzo Donati‭ · 2023-08-05T15:50:16Z (9 months ago)
Retagged.
#3: Post edited by user avatar Lorenzo Donati‭ · 2021-10-11T12:28:36Z (over 2 years ago)
Substituted formula images with MathJax syntax (with corrections). Some grammar edit.
Voltage of  tank circuit is invalid
  • In a [previous](https://electrical.codidact.com/posts/282585) question we found that for a critical damped oscillation:
  • ![Hi](https://electrical.codidact.com/uploads/YFDDpFztyswF1qeinfqvuZVj)
  • But if we integrate to find the voltage through the capacitor:
  • ![hI](https://electrical.codidact.com/uploads/Yx3t6FRnMKZTqBAPGycqk2ra)
  • the integral is always a positive value which doesnt make any sense since the capacitor is being discharged.
  • What am I doing wrong here?Help appreciated!
  • In a [previous](https://electrical.codidact.com/posts/282585) question we found that for a critically damped oscillation:
  • $$
  • I(t) = 2 t e^{-0.5 t}
  • $$
  • But if we integrate to find the voltage through the capacitor:
  • $$
  • V_{CO} + \frac{1}{C} \cdot \int_0^t{I(t)}dt
  • $$
  • the integral is always a positive value which doesn't make any sense since the capacitor is being discharged.
  • What am I doing wrong here? Help appreciated!
#2: Post edited by user avatar MissMulan‭ · 2021-07-13T12:32:07Z (almost 3 years ago)
  • In a [previous](https://electrical.codidact.com/posts/282585) question we found that for a critical damped oscillation:
  • ![Hi](https://electrical.codidact.com/uploads/YFDDpFztyswF1qeinfqvuZVj)
  • But if we integrate to find the voltage through the capacitor:
  • ![Hi](https://electrical.codidact.com/uploads/ZCKF5vt61PecH38JsLeti9KW)
  • the integral is always a positive value which doesnt make any sense since the capacitor is being discharged.
  • What am I doing wrong here?Help appreciated!
  • In a [previous](https://electrical.codidact.com/posts/282585) question we found that for a critical damped oscillation:
  • ![Hi](https://electrical.codidact.com/uploads/YFDDpFztyswF1qeinfqvuZVj)
  • But if we integrate to find the voltage through the capacitor:
  • ![hI](https://electrical.codidact.com/uploads/Yx3t6FRnMKZTqBAPGycqk2ra)
  • the integral is always a positive value which doesnt make any sense since the capacitor is being discharged.
  • What am I doing wrong here?Help appreciated!
#1: Initial revision by user avatar MissMulan‭ · 2021-07-13T11:45:05Z (almost 3 years ago)
Voltage of  tank circuit is invalid
In a [previous](https://electrical.codidact.com/posts/282585) question we found that for a critical damped oscillation:

![Hi](https://electrical.codidact.com/uploads/YFDDpFztyswF1qeinfqvuZVj)

But if we integrate to find the voltage through the capacitor:

![Hi](https://electrical.codidact.com/uploads/ZCKF5vt61PecH38JsLeti9KW) 

the integral is always  a positive value which doesnt make any sense since the capacitor is being discharged.

What am I doing wrong here?Help appreciated!