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Q&A Band pass filter given cutoff frequency and bandwidth

My mistake was taking the third relationship $\frac{1}{R C}$ which says how to find the bandwidth of a parallel RLC filter but we have a series RLC filter. Now solving the system : $$ LC = 100...

posted 3y ago by MissMulan‭ · edited 3y ago by MissMulan‭

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#2: Post edited by

MissMulan‭ · 2022-07-15T18:16:15Z (almost 3 years ago)

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~~My mistake was taking the third relationship $\frac{1}{R C}$ which says how to find the bandwidth of a parallel RLC circuit but we have a series RLC series.~~
Now solving the system : $L C = 100020001, \frac{R}{L} = 2$
gives us the correct ratio between C1 and R1 and L1 with more detail:
C1:L1 = 100020001:1
C1:R1 = 100020001:2

My mistake was taking the third relationship $\frac{1}{R C}$ which says how to find the bandwidth of a parallel RLC filter but we have a series RLC filter.
Now solving the system : $L C = 100020001, \frac{R}{L} = 2$
gives us the correct ratio between C1 and R1 and L1 with more detail:
C1:L1 = 100020001:1
C1:R1 = 100020001:2

#1: Initial revision by

MissMulan‭ · 2022-07-15T18:15:44Z (almost 3 years ago)

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My mistake was taking the third relationship $$ \frac{1}{RC} $$ which says how to find the bandwidth of a parallel RLC circuit but we have a series RLC series.

Now solving the system : $$ LC  = 100020001 , \frac{R}{L} = 2 $$ 

gives us the correct ratio between C1 and R1 and L1 with more detail:

C1:L1 = 100020001:1

C1:R1 = 100020001:2

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