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The thermal stability coefficient is defined to be: $S = \frac{dI_{C}}{dI_{CBO}}$ where $I_{CBO}$ is the reverse current of the BJT when voltage isnt applied to the base of the BJT. In case of a ...
#2: Question closed
by
Nick Alexeev
·
2023-07-28T16:21:34Z (over 1 year ago)
#1: Initial revision
by
MissMulan
·
2022-10-24T20:22:00Z (about 2 years ago)
Thermal stability coefficient
The thermal stability coefficient is defined to be:
$S = \frac{dI_{C}}{dI_{CBO}}$ where $I_{CBO}$ is the reverse current of the BJT when voltage isnt applied to the base of the BJT.
In case of a BJT biased with 2 sources $I_{C} = \beta \cdot I_{b}+(\beta +1)I_{CBO}$
However my textbook says that $S = \frac{1+\beta}{1-\beta\frac{dI_{b}}{dI_{C}}}$
however I dont get why that is the case.Any help?