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Q&A Thermal stability coefficient [closed]

The thermal stability coefficient is defined to be: $S = \frac{dI_{C}}{dI_{CBO}}$ where $I_{CBO}$ is the reverse current of the BJT when voltage isnt applied to the base of the BJT. In case of a ...

0 answers  ·  posted 1y ago by MissMulan‭  ·  closed 9mo ago by Nick Alexeev‭

#2: Question closed by user avatar Nick Alexeev‭ · 2023-07-28T16:21:34Z (9 months ago)
#1: Initial revision by user avatar MissMulan‭ · 2022-10-24T20:22:00Z (over 1 year ago)
Thermal stability coefficient
The thermal stability coefficient is defined to be:

$S = \frac{dI_{C}}{dI_{CBO}}$ where $I_{CBO}$ is the reverse current of the BJT when voltage isnt applied to the base of the BJT.

In case of a BJT biased with 2 sources $I_{C} = \beta \cdot I_{b}+(\beta +1)I_{CBO}$

However my textbook says that $S = \frac{1+\beta}{1-\beta\frac{dI_{b}}{dI_{C}}}$

however I dont get why that is the case.Any help?