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Q&A How can I fix this 4-20 mA current loop to source current that matches current sink on its input?

I'd rather use the AD4111 as a high-side current sensor, instead of creating an "inverter" which would generate an equal and opposite current. Each current input of the AD4111 (IINx+ and IINx-) is...

posted 1y ago by Nick Alexeev‭

Answer
#1: Initial revision by user avatar Nick Alexeev‭ · 2023-04-23T20:58:11Z (over 1 year ago)
I'd rather use the AD4111 as a high-side current sensor, instead of creating an "inverter" which would generate an equal and opposite current.

Each current input of the AD4111 (IINx+ and IINx-) is essentially a differential voltage input with a built-in 50 Ω resistor between them.  It can work as a high-side current sensor.  (In the ADAD7111 reference design it's hard-wired as a low-side current sensor, but that's not the only option.)  The current sense inputs are rail-to-rail (the voltages at IINx+ and IINx- can be anywhere between AVSS and AVDD, inclusive).

So, the feedback part of the scheme could look like this:

![sketch](https://electrical.codidact.com/uploads/yfsxvlqnhpvqd0u004odj9x43r3t)