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It all depends on what is connected between the main board and this "hat" board. Your schematic doesn't show any of these connections, so we can't really tell. In the end, the high current loop s...
Answer
#2: Post edited
by
Olin Lathrop
·
2024-11-29T15:41:02Z (19 days ago)
- It all depends on what is connected between the main board and this "hat" board. Your schematic doesn't show any of these connections, so we can't really tell.
In the end, the high current loop should be isolated from everything else. In your context, V3 would be an isolated supply. The circuit in the blue box would be referenced to the same isolated ground as the supply. You will then need some sort of isolation for the signal that turns on M1. One obvious way to do that would be to replace Q1 with an opto-isolator. Of course you need to check that the reaction time is still fast enough in that case.
- It all depends on what is connected between the main board and this "hat" board. Your schematic doesn't show any of these connections, so we can't really tell.
- In the end, the high current loop should be isolated from everything else. In your context, V3 would be an isolated supply. The circuit in the blue box would be referenced to the same isolated ground as that supply. You will then need some sort of isolation for the signal that turns on M1. One obvious way to do that would be to replace Q1 with an opto-isolator. Of course you need to check that the reaction time is still fast enough in that case.
#1: Initial revision
by
Olin Lathrop
·
2024-11-29T15:40:06Z (19 days ago)
It all depends on what is connected between the main board and this "hat" board. Your schematic doesn't show any of these connections, so we can't really tell. In the end, the high current loop should be isolated from everything else. In your context, V3 would be an isolated supply. The circuit in the blue box would be referenced to the same isolated ground as the supply. You will then need some sort of isolation for the signal that turns on M1. One obvious way to do that would be to replace Q1 with an opto-isolator. Of course you need to check that the reaction time is still fast enough in that case.