Activity for Circuit fantasistâ€
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Comment | Post #286215 |
@TonyStewart, you got me thinking again about the difference between "voltage" and "voltage drop"... and I think I found an even better answer than before...
I think that when we charge a capacitor from a voltage source, there is a voltage across the source and a voltage drop across the capacitor;... (more) |
— | over 1 year ago |
| Edit | Post #286649 |
Post edited: Minor edit |
— | almost 2 years ago |
| Edit | Post #286649 |
Post edited: Minor edit |
— | almost 2 years ago |
| Edit | Post #286649 |
Post edited: Specifying |
— | almost 2 years ago |
| Edit | Post #286649 |
Post edited: Added conclusion |
— | almost 2 years ago |
| Edit | Post #286649 |
Post edited: Minor edit |
— | almost 2 years ago |
| Edit | Post #286649 |
Post edited: CB vs CE representation |
— | almost 2 years ago |
| Edit | Post #286649 |
Post edited: Structuring |
— | almost 2 years ago |
| Edit | Post #286649 | Initial revision | — | almost 2 years ago |
| Answer | — |
A: Find Q point in common base BJT configuration Load line ========= Formal "explanation" > In common emitter collector we just draw a line from the vertical axis (Ic) at the point (0,VCC/RC) to the horizontal axis at the point(VCC,0) and where that line intersects with the IC/VCE curve for some specific IB, there is our operating point… ... (more) |
— | almost 2 years ago |
| Edit | Post #284873 |
Post edited: Inserted picture of MICROLAB periphery |
— | about 2 years ago |
| Edit | Post #284873 |
Post edited: Minor edit |
— | about 2 years ago |
| Comment | Post #286215 |
It is interesting to answer such a question, "What is across a capacitor - voltage or voltage drop?" (more) |
— | about 2 years ago |
| Edit | Post #284873 |
Post edited: Structuring (added another subtitle) |
— | about 2 years ago |
| Edit | Post #284873 |
Post edited: Italicized name |
— | about 2 years ago |
| Edit | Post #286148 |
Post edited: Minor edit |
— | about 2 years ago |
| Edit | Post #286148 | Initial revision | — | about 2 years ago |
| Answer | — |
A: What reactance actually is? Here is another "functional explanation" of this phenomenon (see also my RG question). General feature. Unlike resistors that directly decrease current, both capacitors and inductors do it by subtracting their voltage from the source voltage creating this current. You can think of them as varyin... (more) |
— | about 2 years ago |
| Comment | Post #285392 |
I understand... Thanks for the comment though. (more) |
— | about 2 years ago |
| Comment | Post #285392 |
I guess you have some reason to write this... but I can't guess what.
According to my ideas, the internal resistance of the input sources is added to the resistance of the input resistors. As a result, the gain of the inverting and non-inverting input of this simple differential amplifier becomes ... (more) |
— | about 2 years ago |
| Edit | Post #285392 |
Post edited: Rearranged and refined |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: About the basic idea |
— | over 2 years ago |
| Comment | Post #285392 |
Thank you for the useful feedback. I have planned to make a similar story about basic transistor circuits. Happy New Year! (more) |
— | over 2 years ago |
| Comment | Post #285392 |
Thanks! Happy New Year! (more) |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: About the position of virtual ground in single-ended mode |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Considered analogy for the common mode |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Added another example |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Minor edit |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Minor edit |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Minor edit |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: More about the mixed mode |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Added another related link |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Revealed contradiction about the middle point between the resistors Rg/2 |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: About the single-ended differential mode |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Made connection with bootstrapping |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Edited tags |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Explained mixed mode |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Figuratively said - "fighting" and "helping" |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: About the current in the "pure common mode" |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Minor edit |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: About the current flowing between the two op-amp outputs |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Minor edit |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Minor edit |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: More about how to explore the circuit operation |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Minor edit |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Minor edit |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Enlarged description of the differential mode |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Structured paper; added clear pictures |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Replaced a picture with cropped one |
— | over 2 years ago |
| Edit | Post #285392 |
Post edited: Replaced picture with more qualitative |
— | over 2 years ago |