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Comments on Voltage of tank circuit is invalid

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Voltage of tank circuit is invalid

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In a previous question we found that for a critically damped oscillation:

$$ I(t) = 2 t e^{-0.5 t} $$

But if we integrate to find the voltage through the capacitor:

$$ V_{CO} + \frac{1}{C} \cdot \int_0^t{I(t)}dt $$

the integral is always a positive value which doesn't make any sense since the capacitor is being discharged.

What am I doing wrong here? Help appreciated!

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1 comment thread

When it is critically damped, there is not oscillation. (1 comment)
When it is critically damped, there is not oscillation.
Andy aka‭ wrote about 3 years ago

When it is critically damped, there is not oscillation.