Electrical Engineering

I am studying for a test in control systems and we have a practical part which is to program a analog computer.

The variable resistor is basically a voltage divider between VCC and VEE and you can change the output voltage by changing the position of the potentiometer.

We set the potentiometer to multiply the signal it sees by 0.4 then return to the input of a amplifier.Next to the potentiometer there are 3 pins the top pin and bottom pin are connected internally to VCC and VEE and the middle pin is the voltage division.When we are done setting the value of the potentiometer and connect the middle pin to the input of a amplifier and we are ready to measure the output voltage with a oscilloscope do we still keep the top and bottom pins plugged to power or not?Will I create a short if I keep the top and bottom pins plugged to power?

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Confusion in operation of analog computer

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