Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

Bit-rate vs Baud-rate

+2
−0

I am really confused how the terms bit-rate are baud-rate are used in electronics. I never bothered thinking about baud-rate being different than bit-rate before. But recently, one of my teachers told baud-rate being the maximum no. of changes in the bit that can occur during the data transfer.

I really want to visualize how they are different from each other.

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.
Why should this post be closed?

0 comment threads

3 answers

You are accessing this answer with a direct link, so it's being shown above all other answers regardless of its score. You can return to the normal view.

+1
−1

Baud rate is about the speed of bit slots in the channel or symbols. Bit rate is the rate at which actual data is transmitted.

Put another way, baud rate is what you see when you look at a scope trace of a communication signal. Bit rate is how fast data gets from one end to the other.

The bit rate can be both higher and lower than the baud rate due to encoding and packaging schemes. Modern high speed protocols do various fancy things to encode more than one bit of data into each symbol, so the bit rate is often higher than the baud rate.

However, for most "ordinary" protocols (UART, CAN, IIC, SPI for example), some of the bit slots are used to delimit and package the information, so the bit rate is lower than the baud rate.

Consider the common UART protocol of 115.2 kBaud, 8 data bits, no parity, and 1 stop bit. Each character requires 10 bit slots to send: 1 start bit, 8 actual data bits, and 1 stop bit. Since the baud rate is 115.2 k/s, each bit slot is 8.68 µs long. A whole character therefore takes 86.8 µs to transmit. A total of 8 payload bits are transported during that time, so the bit rate is (8 bits)/(86.8 µs) = 92.2 kBits/s.


@TonyStewart‭ wrote:

Can you give an example where Baud Rate is higher than Bit Rate?

I did. See previous paragraph.

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.

1 comment thread

General comments (6 comments)
+6
−0

In short:

  • The baud rate is the symbol transmission rate.

  • The bit rate is the data transmission rate.

(A "symbol", in this context, is simply a group of some relatively arbitrary, non-zero number of bits, transmitted as one atomic unit.)

While in simple cases the two can be identical, as soon as one symbol encodes more than one bit, they diverge. And that is incredibly common in modern data transmission systems.

Therefore, in practice, the bit rate of a channel will almost always be higher than its baud rate.

The baud rate matters more when you are interested in the requirements imposed on the data transmission physical link layer (such as a radio link's spectrum bandwidth, or the transition times in a modulator). The bit rate, on the other hand, matters more when you are interested in how much data can actually be transmitted within a given time period. Both are useful metrics, but as they measure different quantities, they answer different questions.

As an example, consider quadrature amplitude modulation; 4096-QAM encodes 12 bits (212 = 4096) per symbol. Therefore, the baud rate for a 4096-QAM channel is 2-12 = 1/4096 of the data rate of the same channel.

In practice, some of those bits being transmitted will, in turn, likely be used for various kinds of metadata; things like frame headers, checksums, start and stop bits, on-bus addressing, forward error correction, and so on. In places, data is deliberately stretched out, not uncommonly to improve error handling or simplify synchronization. For example, SATA uses 8b/10b encoding on the physical link layer, and CDDA extends data multiple times for various reasons between the raw audio sample data and what's actually on the physical storage medium. Designs like these will reduce the rate at which useful payload data can be transmitted below that of the raw channel bit rate, and that is relevant for the amount of time it takes to usefully transmit some given amount of data, but they do not change the bit rate of the channel itself.

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.

1 comment thread

General comments (2 comments)
+1
−0

Baudrate is most often used to mean payload data bits/second. Simply picture a manchester encoded protocol, where each data bit corresponds to 2 physical bits in the raw data frame. If you have a bitrate of 9600, you will then have a baudrate of 4800.

There's lots of tutorials out there that describe this in detail, see for example https://www.electronicdesign.com/technologies/communications/article/21802272/whats-the-difference-between-bit-rate-and-baud-rate

"one of my teachers told baud-rate being the maximum no. of changes in the bit that can occur during the data transfer" No, that's not correct. That sounds more like Hamming distance.

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.

0 comment threads

Sign up to answer this question »