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I have a question about this circuit:(critically damped oscillation) For a critically damped oscillation for a series RLC circuit the equation of current has this form I(t)=D1te^(-at)+D2e^(-at) ...

2 answers · posted 3y ago by MissMulan‭ · edited 9mo ago by Lorenzo Donati‭

Question capacitor inductor tank-circuit

#6: Post edited by

Lorenzo Donati‭ · 2023-08-12T10:24:55Z (9 months ago)

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capacitor current inductor

capacitor inductor tank-circuit

#5: Question reopened by

Olin Lathrop‭ · 2021-07-07T21:13:36Z (almost 3 years ago)

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#4: Post edited by

MissMulan‭ · 2021-07-07T19:45:56Z (almost 3 years ago)

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I have a question about this circuit:(critically damped oscillation)
![SeeMe](https://electrical.codidact.com/uploads/bcvK5rTywmz7b7MJYmqBgeV9)
For a critically damped oscillation for a series RLC circuit the equation of current has this form I(t)=D1te^(-at)+D2e^(-at) where D2 =I(0+) and D1-aD2 = dI(0+)/dt=VL/L.
In the 2nd circuit due to L1 :I(0)=I(0+)=0A and by applying KVL in VL1=-VC1=-2V
And by substituting the values we get D1=-2A/s and D2 = 0A and we end up with an equation of I(t)=-2te^(-0.5t) but this cant be correct.What am I doing wrong?

I have a question about this circuit:(critically damped oscillation)
![SeeMe](https://electrical.codidact.com/uploads/bcvK5rTywmz7b7MJYmqBgeV9)
For a critically damped oscillation for a series RLC circuit the equation of current has this form I(t)=D1te^(-at)+D2e^(-at) where D2 =I(0+) and D1-aD2 = dI(0+)/dt=VL/L.
Due to L1 :I(0)=I(0+)=0A and by applying KVL in VL1=-VC1=-2V
And by substituting the values we get D1=-2A/s and D2 = 0A and we end up with an equation of I(t)=-2te^(-0.5t) but this cant be correct.What am I doing wrong?

#3: Post edited by

MissMulan‭ · 2021-07-07T19:45:08Z (almost 3 years ago)

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~~I have a question about the 2nd circuit:(critically damped oscillation)~~
~~![SeeMe](https://electrical.codidact.com/uploads/Bhzjb341E3trR3DQ3SjUE9bY)~~
For a critically damped oscillation for a series RLC circuit the equation of current has this form I(t)=D1te^(-at)+D2e^(-at) where D2 =I(0+) and D1-aD2 = dI(0+)/dt=VL/L.
In the 2nd circuit due to L1 :I(0)=I(0+)=0A and by applying KVL in VL1=-VC1=-2V
And by substituting the values we get D1=-2A/s and D2 = 0A and we end up with an equation of I(t)=-2te^(-0.5t) but this cant be correct.What am I doing wrong?

I have a question about this circuit:(critically damped oscillation)
![SeeMe](https://electrical.codidact.com/uploads/bcvK5rTywmz7b7MJYmqBgeV9)
For a critically damped oscillation for a series RLC circuit the equation of current has this form I(t)=D1te^(-at)+D2e^(-at) where D2 =I(0+) and D1-aD2 = dI(0+)/dt=VL/L.
In the 2nd circuit due to L1 :I(0)=I(0+)=0A and by applying KVL in VL1=-VC1=-2V
And by substituting the values we get D1=-2A/s and D2 = 0A and we end up with an equation of I(t)=-2te^(-0.5t) but this cant be correct.What am I doing wrong?

#2: Question closed by

Olin Lathrop‭ · 2021-07-07T17:55:52Z (almost 3 years ago)

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#1: Initial revision by

MissMulan‭ · 2021-07-07T16:50:49Z (almost 3 years ago)

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Critically damped oscillation issue

I have a question about the 2nd circuit:(critically damped oscillation)

![SeeMe](https://electrical.codidact.com/uploads/Bhzjb341E3trR3DQ3SjUE9bY)

For a critically damped oscillation for a series RLC circuit the equation of current has this form I(t)=D1te^(-at)+D2e^(-at) where D2 =I(0+) and D1-aD2 = dI(0+)/dt=VL/L.

In the 2nd circuit due to L1 :I(0)=I(0+)=0A and by applying KVL in VL1=-VC1=-2V

And by substituting the values we get D1=-2A/s and D2 = 0A and we end up with an equation of I(t)=-2te^(-0.5t) but this cant be correct.What am I doing wrong?

capacitor current inductor

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