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Q&A H(jω) does not exist for unstable systems, but we still use it when designing controllers - contradiction?

According to Signal processing and linear systems by Lathi, the transfer function $H(j\omega)$ does not exist for systems with poles in the RHP: - This makes sense to me, since $H(j\omega) = \fr...

3 answers  ·  posted 3y ago by Carl‭  ·  edited 1y ago by Lorenzo Donati‭

#4: Post edited by user avatar Lorenzo Donati‭ · 2023-08-12T13:30:33Z (about 1 year ago)
Retagged.
#3: Post edited by user avatar Canina‭ · 2022-02-01T09:07:55Z (almost 3 years ago)
  • H(jw) does not exist for unstable systems, but we still use it when designing controllers - contradiction?
  • H(jω) does not exist for unstable systems, but we still use it when designing controllers - contradiction?
According to _Signal processing and linear systems_ by Lathi, the transfer function \$H(j\omega)\$ does not exist for systems with poles in the RHP: -

![Lathi](https://electrical.codidact.com/uploads/GaNJKtJSqPBD9L9uzwprts6Z)

This makes sense to me, since \$H(j\omega) = \frac{Y(j\omega)}{X(j\omega)} \$. However, since the system is unstable \$Y \$ is unbounded (and growing) and the fourier transform doesn't exist for such functions. So \$Y(j\omega)\$ doesn't exist and therefore, \$H(j\omega) \$ must be meaningless for unstable systems.

BUT! we use \$H(j\omega) \$ when designing controllers for unstable systems anyway - and it works. We look at the Bode Plot, we look at the Nyquist Plot both of which you need to know \$H(j\omega)\$ and design a controller based on what we see - and the controller actually works! 

How can this be? How can there be this contradiction between systems and signals theory and control theory? It seems that concepts like **region of convergence** and **existence of fourier integral** are only dealt with on coursework and once that's done, you don't hear from them ever again.
#2: Post edited by user avatar Carl‭ · 2022-02-01T08:37:01Z (almost 3 years ago)
  • \$H(j\omega)\$ does not exist for unstable systems, but we still use it when designing controllers - contradiction?
  • H(jw) does not exist for unstable systems, but we still use it when designing controllers - contradiction?
#1: Initial revision by user avatar Carl‭ · 2022-02-01T08:35:55Z (almost 3 years ago)
\$H(j\omega)\$ does not exist for unstable systems, but we still use it when designing controllers - contradiction?
According to _Signal processing and linear systems_ by Lathi, the transfer function \$H(j\omega)\$ does not exist for systems with poles in the RHP: -

![Lathi](https://electrical.codidact.com/uploads/GaNJKtJSqPBD9L9uzwprts6Z)

This makes sense to me, since \$H(j\omega) = \frac{Y(j\omega)}{X(j\omega)} \$. However, since the system is unstable \$Y \$ is unbounded (and growing) and the fourier transform doesn't exist for such functions. So \$Y(j\omega)\$ doesn't exist and therefore, \$H(j\omega) \$ must be meaningless for unstable systems.

BUT! we use \$H(j\omega) \$ when designing controllers for unstable systems anyway - and it works. We look at the Bode Plot, we look at the Nyquist Plot both of which you need to know \$H(j\omega)\$ and design a controller based on what we see - and the controller actually works! 

How can this be? How can there be this contradiction between systems and signals theory and control theory? It seems that concepts like **region of convergence** and **existence of fourier integral** are only dealt with on coursework and once that's done, you don't hear from them ever again.