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Suppose we have this graph: How can we find the operating point (Q)?In common emitter collector we just draw a line from the vertical axis (Ic) at the point (0,VCC/RC) to the horizontal axis a...
#2: Post edited
- Suppose we have this graph:
- ![](https://electrical.codidact.com/uploads/34eS35VabSgkqjSCNoXJgMGR)
- How can we find the operating point (Q)?In common emitter collector we just draw a line from the vertical axis (Ic) at the point (0,VCC/RC)
- to the horizontal axis at the point(VCC,0) and where that line intersects with the IC/VCE curve for some specific IB , there is our operating point but now 1)we have VCB instead of VCE and 2)VCB may take negative values.
- Help appreciated!
- Suppose we have this graph:
- ![](https://electrical.codidact.com/uploads/34eS35VabSgkqjSCNoXJgMGR)
- How can we find the operating point (Q)?In common emitter collector we just draw a line from the vertical axis (Ic) at the point (0,VCC/RC)
- to the horizontal axis at the point(VCC,0) and where that line intersects with the IC/VCE curve for some specific IB , there is our operating point but now 1)we have VCB instead of VCE and 2)VCB may take negative values.
- Here is the circuit:
- ![](https://electrical.codidact.com/uploads/f47eY3h5c1bdEb8JEFMHeN74)
- Help appreciated!
#1: Initial revision
Find Q point in common base BJT configuration
Suppose we have this graph: ![](https://electrical.codidact.com/uploads/34eS35VabSgkqjSCNoXJgMGR) How can we find the operating point (Q)?In common emitter collector we just draw a line from the vertical axis (Ic) at the point (0,VCC/RC) to the horizontal axis at the point(VCC,0) and where that line intersects with the IC/VCE curve for some specific IB , there is our operating point but now 1)we have VCB instead of VCE and 2)VCB may take negative values. Help appreciated!