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If we have the transfer function of a LC high pass filter: $H(s) = \frac{sL}{sL+\frac{1}{sC}}$ If we want to find the pole of that filter in the end we get: $s = \frac{j}{\sqrt{LC}}$ and for a ...
#2: Post edited
by
Lorenzo Donati
·
2023-08-13T19:17:45Z (over 1 year ago)
Retagged.
#1: Initial revision
by
MissMulan
·
2022-07-10T18:51:42Z (over 2 years ago)
Complex frequency of a pole
If we have the transfer function of a LC high pass filter:
$H(s) = \frac{sL}{sL+\frac{1}{sC}}$
If we want to find the pole of that filter in the end we get:
$s = \frac{j}{\sqrt{LC}}$
and for a sinuisodal input signal $s = j\omega$ the pole exists at the resonant frequency $\omega_{r}$
However if we dont apply a sinuisodal signal at the input s may become a complex number->the frequency of the pole may be complex.But what physical meaning does it have?