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Q&A Potentiostat Clarification needed

What the top part of the circuit really does is drive the counter electrode to whatever it takes to null out the voltage on the reference electrode. The null comes from what the positive input of ...

posted 1d ago by Olin Lathrop‭

Answer
#1: Initial revision by user avatar Olin Lathrop‭ · 2025-05-06T18:48:39Z (1 day ago)
What the top part of the circuit really does is drive the counter electrode to whatever it takes to null out the voltage on the reference electrode.  The null comes from what the positive input of IC2 is set at, which is ground in this case.

I'm not familiar with these types of sensors, but it looks like the reference electrode is run at high impedance with the counter electrode adjusted to keep the reference electrode voltage at 0.  The working electrode is then held at 0 V (or very close to it) and its current measured.

Note that opamp IC2 is configured as a transconductance amp.  In other words, its output is proportional to the input current.  The negative input is held at the same voltage as the positive input (0 in this case), and the output voltage shows what current it takes to do that.

Don't get confused by the FET.  It is only there for startup reasons.  It is high impedance between source and drain during normal operation.