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Activity for Andy aka‭

Type On... Excerpt Status Date
Edit Post #276267 Post edited:
almost 4 years ago
Edit Post #276267 Post edited:
almost 4 years ago
Edit Post #276267 Initial revision almost 4 years ago
Answer A: Pi-Filter for EMC
> What would be the main considerations to use Pi-filters for EMC? Using the filter correctly and understanding its limitations EMC or EMI (electromagnetic interference) is noted for its high frequency energy content. Applying a \$\pi\$ filter like the one below can significantly attenuate tho...
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almost 4 years ago
Edit Post #276262 Post edited:
almost 4 years ago
Comment Post #276263 @Olin I'm using google chrome and I still can't see it - bug alert!!!
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almost 4 years ago
Edit Post #276262 Post edited:
almost 4 years ago
Edit Post #276262 Post edited:
almost 4 years ago
Edit Post #276262 Post edited:
almost 4 years ago
Edit Post #276262 Post edited:
almost 4 years ago
Comment Post #276263 @Olin your image is not showing. I am going to add more sections to this answer so it might be that your answer "what Andy described" might not hit the mark in terms of the fullness of what I hope to complete!
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almost 4 years ago
Edit Post #276262 Post edited:
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Edit Post #276261 Post edited:
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Edit Post #276262 Post edited:
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Edit Post #276261 Post edited:
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Edit Post #276262 Post edited:
almost 4 years ago
Edit Post #276262 Post edited:
almost 4 years ago
Edit Post #276262 Post edited:
almost 4 years ago
Edit Post #276261 Post edited:
almost 4 years ago
Edit Post #276262 Initial revision almost 4 years ago
Answer A: Low loss impedance matching without a transformer
Low-pass impedance transformation Image alt text Theory Input Impedance: - $$Z{IN} = j\omega L + \dfrac{\dfrac{RL}{j\omega C}}{RL + \dfrac{1}{j\omega C}} = j\omega L +\dfrac{RL}{1 + j\omega RL C} = \dfrac{j\omega L - \omega^2 RL LC + RL}{1 + j\omega RL C}$$ Multiply numerator and denom...
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almost 4 years ago
Edit Post #276261 Initial revision almost 4 years ago
Question Low loss impedance matching without a transformer
I have a signal at 10 MHz produced from a 50 Ω source. How can I match that to a 300 Ω load with low losses without using an RF transformer (space constraints)? Are there any circuits and formulas that can help me achieve this?
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almost 4 years ago
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Edit Post #276250 Post edited:
almost 4 years ago
Edit Post #276250 Post edited:
almost 4 years ago
Edit Post #276250 Initial revision almost 4 years ago
Answer A: Moving average that uses less memory?
I'm adding to Olin's answer with a little bit of theory (from the standpoint of an EE) and I'm also showing a 2nd order IIR filter. The 2nd order filter is based on cascading two 1st order stages with an additional feedback loop to control Q factor (or \$\zeta\$). Both these filters are IIR types...
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almost 4 years ago
Edit Post #276225 Post edited:
almost 4 years ago
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Comment Post #276225 @Olin yes of course. However this isn't a real design and I purposefully tried to be a little extreme with things to explain the theory (still ongoing).....
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almost 4 years ago
Edit Post #276225 Post edited:
almost 4 years ago
Edit Post #276225 Post edited:
almost 4 years ago