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Comments on Constant Current Load Circuit with Op Amp

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Constant Current Load Circuit with Op Amp

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Hi, I built a constant current load following the circuit from https://www.instructables.com/id/DIY-Constant-current-load/

But my op amp gets destroyed after a few minutes. The transistor or the op amp didnt get hot to the touch. After replacing the op amp the circuit works again for a short time.

Am I at fault or is the circuit wrong? Tested at 10V 0.5A.

Image alt text

P.S. It is working again as of now. But still I have destroyed a couple op amp. Is there a better circuit design? Like mentioned here https://electronics.stackexchange.com/questions/371864/constant-current-load-op-amp-ref-voltage-limit

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General comments (3 comments)
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let me begin with a schematic for an adjustable current source with a simple load:

Image

The operation is simple: The current I inside R1 gives rise a voltage drop equal to

I/R1 (= I if R1 = 1).

So the oamp will set the voltage to the gate of the mosfet in such a way that

I/R1 = V_pot, that is, I = R1 V_pot = V_pot if R1 = 1.

Since V_pot varies between 0 and 5V, I varies between 0 and 5 amp. So, the resistor should be rated for 25W (=1 ohm * (5A)^2 ) otherwise it will burn (assuming your supply and mosfet will not burn before it). I suggest to put a 500k resistor between the pot and the 5V supply, in order to make V_pot vary between 0 and 2.5V. In this way, the maximal power dissipated by the resistor will be about 5W.

Now, regarding the schematic you posted, it is not a constant current source for an usual load, but a constant current source for testing a battery, that is, the battery under test IS the power supply (and there is no load). Apart from that, everything is the same. That means that it should work up to 5V if the battery is able to feed 5A. In this way, you can measure the maximal current the battery is able to deliver (or more precisely, if it fits its compliance), by simply measuring the voltage at R1 (recall that the voltage is equal to the current because R1 = 1Ohm). Normally, there is no reason the circuit do not work, except that you may have wired the oamp wrongly, or a perverse connection etc. Nevertheless, to religiously protect the oamp, I suggest to put a 1k resistor between the out of the oamp and the gate of the mosfet. This will also prevent possible destructive oscillations and everything should work fine. So, the improvements I suggest are:

  1. 500k resistor between the pot and the 5V supply, or a resistor rated 25W.
  2. 1k resistor between the out of the oamp and the gate of the mosfet
  3. Oh, and of course a heat sink for the transistor, otherwise it may well burn.
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General comments (1 comment)
General comments
timelyfiasco‭ wrote about 4 years ago

Thank you. This explanation is at my level. :) I make sure nothing overheats as I used it. But I wondered why the op amp failed before. I did notice the 5V supply consuming twice the current as I turn R2 to increase the current thru the MOSFET. That is why I am worried if there is lacking in my circuit. I will try making a new one with 1k resistor.