Comments on Current and voltage in AC circuits without impedance
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Current and voltage in AC circuits without impedance
How can we find the equation of current and voltage of a capacitor circuit if the input voltage is AC without using the impedance formula Xc = -jωC?.
We have for homework to find the equation of current of the circuit and the equation of voltage of the capacitor assuming we just connected the voltage source to the circuit
We can say that Ic = C1*dV/dt and Vc = Vo(0)+∫I(t)dt and from Ohm's law we can say that dV/dt = d/dt(V1-IR1) but what is the value of I?
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Since this is homework, I'm not just going to give you the answer.
When all else fails, go back to first principles. That's what handy shortcuts, like using impedance, were derived from.
In this case, you'll end up with a system of differential equations. You have already written the equation for the capacitor current as a function of its voltage. Note that the capacitor and resistor currents are the same. You should be able to write the equation for the resistor current.
The voltage across the two components are also related, in that their sum must equal the driving voltage.
After you write the various individual equations, you solve the set of equations to get the capacitor voltage as a function of the driving voltage. Note that this assumes you've already had your differential equations course.
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