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Comments on Find Q point in common base BJT configuration

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Find Q point in common base BJT configuration

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Suppose we have this graph:

How can we find the operating point (Q)?In common emitter collector we just draw a line from the vertical axis (Ic) at the point (0,VCC/RC) to the horizontal axis at the point(VCC,0) and where that line intersects with the IC/VCE curve for some specific IB , there is our operating point but now 1)we have VCB instead of VCE and 2)VCB may take negative values.

Here is the circuit:

Help appreciated!

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1 comment thread

Show the circuit. (3 comments)
Show the circuit.
Olin Lathrop‭ wrote almost 2 years ago

Show the circuit. The operating point depends on other circuit elements around the transistor.

Andy aka‭ wrote almost 2 years ago

Your graph is for a PNP transistor yet you have drawn an NPN transistor

Olin Lathrop‭ wrote almost 2 years ago

Your new picture shows the basic configuration, but not the specs of what you want the circuit to achieve. Is it amplifying a digital signal? Analog? What impedance? Voltage/current range? The picture is also obnoxiously large. Being rude to the volunteers you seek a favor from is not a good way to get that favor.