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Comments on Modelling tunnel diode relaxation oscillator

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Modelling tunnel diode relaxation oscillator

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I have been trying to model this oscillator

I was wondering if we can somehow predict the frequency of the oscillations.For small currents inside a diode from the Shockley diode equation $$ e^{x}-1 = x$$ -> $$I_{D} = \frac{x}{V_{T}}I_{s} \rightarrow \frac{x}{I_{d} } = \frac{V_{T}}{I_{s}}$$ so we can say that for small currents the diode can be replaced with a resistor equal to $$R_{d} = \frac{V_{T}}{I_{s}}$$

Now back to the relaxation oscillator circuit the 2 resistors bias the voltage of the tunnel diode well below $$V_{f}$$ of the tunnel diode so the approximation is valid.But the VI curve of the resistor which replaces the tunnel diode in order to copy the negative differential resistance region must not be a continuous function , it must be discontinuous for voltages from Vp to Vf .Image alt text

Can we estimate that way the frequency of the relaxation oscillator?

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Unless you know the exact formula for the I-V curve, you will never find out anything analytically. Fair warning: very unlikely you will get such formula, since they are strongly non-linear in nature. The analysis of such oscillators is done based on approximations (see the Esaki diode, for example), and it involves a lot of estimations.

But if your purpose is a relaxation oscillator then you'll be much better off using some of the already known circuits: reverse BE junction, multivibrator, comparator, etc. All of them rely on a much more analytically-inclined RC time constant, combined with simple thresholds. The tunnel diode has a continuously variable threshold. Plus, they will likely consume much less current.

If you insist in pursuing the tunnel diode analysis then you should know that the way you started is not the way to go. The small signal does not apply here, since the whole behaviour of the oscillator relies on the point on the I-V curve (as depicted on your I-V curve picture) moving all the time. I can't find the right words to describe now, but a picture should be worth a thousand words: take whatever simulator you want, that lets you zoom in and analyze the waveforms.

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No need for IV curve (2 comments)
No need for IV curve
MissMulan‭ wrote over 2 years ago · edited over 2 years ago

Why do I need the IV curve?I have approximated the tunnel diode to behave like a resistor $$ R_{d} = \frac{V_{T}}{I_{s}}$$ from Vf to Vv and from 0 to Vp

a concerned citizen‭ wrote over 2 years ago

MissMulan‭ And how is that working for you? The whole pronciple of an oscillator is based on the negative resistance. You need to approximate that, too, with another slope, and then the initial slope, too, if you want your oscillations to start. And you'll end up with a PWL approximation which will give you a result, no doubt, but not the one. See, for example, Chua's circuit. So, if you're content with just a "ball-park" value then look no further than the equivalent RL of the circuit. You'll still have to solve the the intersection lines, but you'll likely not get the precise value you're after. And that's why I said this is not done analytically. Don't forget about the low power part and the alternatives.