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Comments on Thermal stability coefficient

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Thermal stability coefficient [closed]

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Closed as unclear by Nick Alexeev‭ on Jul 28, 2023 at 16:21

This question cannot be answered in its current form, because critical information is missing.

This question was closed; new answers can no longer be added. Users with the reopen privilege may vote to reopen this question if it has been improved or closed incorrectly.

The thermal stability coefficient is defined to be:

$S = \frac{dI_{C}}{dI_{CBO}}$ where $I_{CBO}$ is the reverse current of the BJT when voltage isnt applied to the base of the BJT.

In case of a BJT biased with 2 sources $I_{C} = \beta \cdot I_{b}+(\beta +1)I_{CBO}$

However my textbook says that $S = \frac{1+\beta}{1-\beta\frac{dI_{b}}{dI_{C}}}$

however I dont get why that is the case.Any help?

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Andy aka‭ wrote over 1 year ago

The whole basis of this question is something apparently misunderstood in college and, is unable to be confirmed by Miss Mulan. It should now be closed.

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