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Comments on Contactor control - Higher voltage PWM

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Contactor control - Higher voltage PWM

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I have a battery pack that consists of 18650 battery cells(14 cells in series max.). Hence, the voltage of the battery pack will be between 35V and 60V(to be on the safe side)

I am designing a BMS in order to control it with cell monitoring, analog measurements, contactor control, etc. features built-in.

Using the battery HV pack voltage(35-60V), I would like to control a 12V/1.5A coil of a contactor. The reason for that being the fact that the rest of the circuitry could be powered with a 5V/500mA buck converter and not having a 12V/2A supply only for the sake of contactor control would be nice.

Would the following architecture for that purpose work in real life? Is there a better way of doing this? PWM Relay Picture


Here is how the circuit should work. Vpack_analog_input is fed into the micro analog input. The circuit around L1, C1, and D1 serves as a flipped buck converter having an NMOS instead of a PMOS. C2 is providing a low impedance for the switching node because I fear the ringing would cause a significant amount of emissions on the input cable.

The idea is to sense the Vpack and initially allow M2 to be opened for no more than t=L1*Icoil/Vpack , and after that apply PWM to Pwm_Control and limit the duty cycle in order to never have more than a certain threshold of current flowing through L1(to be done through experimenting).

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General comments (2 comments)
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While your basic idea seems fine, I will not enter into this matter, especially after Olin has said he will.

Instead, I will give some other ways to do that, that may be useful in other circumstances.

First of all, there are also inductorless convertors, working with capacitors, that are much cheaper and much less noisy. This one for example, is one of the infinitely many convertors you can found on the market for very cheap. small-buck And they are ready to use, no need to experiment, which can be a mess for a person not well used with convertors.

So, my first advice would be:

if you have no particular reason to build a buck convertor, buy one; after all, why doing by yourself what you can buy at low price.

And if you are not satisfied with bought convertors (e.g. if your supply voltage is too high), my second advice would be:

Take the schematic of a convertor another person has built and tested, and build exactly the same one, adapting if necessary few components.

In fact, for very simple tasks where the load is fixed (as in your question), even a simple LM555 can do, a fact that seems not to be well known. Here is how (I assume you know how to mount 555 oscillators):

  • If the supply voltage is too high, power the 555 with a resistor + zener. The output should have a voltage of 10V (say) in order to switch a mosfet;
  • Mount the 555 as a square wave generator with variable duty cycle;
  • Then use the output of the 555 to switch a Mosfet feeding the load (the coil in your case) from the main supply;
  • add a capacitor in parallel to the load to smooth the voltage;
  • set the duty cycle of the 555 to obtain the desired voltage at the load.

Please, note also the following: you say you have a battery pack where batteries are mounted in series, and it should provide a voltage between 35 and 60V. So, why not manage to introduce a terminal at half the battery chain, or even 1/3 of it? In this way, the voltage would be between 17V - 30V or 12V - 24V, which is easier to deal with.

After there are many ways to abase the voltage efficiently without having to design complicated things, here is a power saver circuit I "invented" once and that worked well for me (in this schematic, I assume there is a 1$ small buck convertor with fixed 5V output, but any other solution mentioned above to obtain a fixed voltage will do):

power_saver

The principle of operation is simple: at startup, the cap is not charged and the Sziklai pair Q1-Q2 conducts the current from the main supply, restricting it to somewhat below 15V because of the Zener D2. As cap C1 is charging, the voltage decreases, until it comes below 5V (and eventually stop conducting). At this point, diode D1 that was preventing the buck convertor to feed the load opens, and the buck convertor feeds the contactor coil at 5V, which is sufficient because of its hysteresis.

Here is a simulation of the above circuit: PS_simul

An advantage of this power saver circuit is that you can control everything easily; in particular, by increasing the value of the cap, you can increase the switching delay time.

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2 comment threads

The image of the website that shows a step-down DC-DC converter doesn't seem to be that of an *induct... (2 comments)
General comments (1 comment)
The image of the website that shows a step-down DC-DC converter doesn't seem to be that of an *induct...
Lorenzo Donati‭ wrote over 1 year ago

The image of the website that shows a step-down DC-DC converter doesn't seem to be that of an inductorless converter, as you hint in the text of your post. That big gray square thing with that 100 printed on it seems just a 100μH inductor to me.

coquelicot‭ wrote about 1 year ago

You may be right. Probably a wrong choice of the example.