Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

Choosing Y value in photoresistor graph

+2
−1

I have designed a graph of the current in a photoresistor related to the brightness of light which hits the photoresistor.

Our professor told us that it is more correct to draw the Current/Brightness graph than the Resistance/Brightness graph of the photoresistor.Why?

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.
Why should this post be closed?

0 comment threads

1 answer

+3
−0

If you truly have a photoresistor, then resistance as a function of brightness makes more sense. It's the resistance that is roughly constant for a fixed brightness as voltage is varied. Put another way, the current is roughly proportional to voltage at any one brightness.

However, if you actually have a photodiode or phototransistor, then the current is roughly constant at a fixed brightness as the voltage is varied. In that case, it does make more sense to plot current as a function of brightness.

It gets even more complicated. The above was assuming the photodiode was used in reverse mode. In other words, you apply reverse voltage to the diode, and the amount the diode "leaks" is proportional to brightness.

Photodiodes can also be used in forward mode, as in solar cells. In that case, they create their own voltage, and current at the same polarity as the voltage so as to produce net power. Neither the open-circuit voltage nor short-circuit current are all that linear with brightness (although the current is closer). The maximum power point shifts in both voltage and current as brightness changes.

You don't have to worry about forward mode with phototransistors. Those are effectively a photodiode in reverse mode amplified by a transistor, but all integrated into one device. There isn't a separate diode junction connected to a separate bipolar transistor.

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.

0 comment threads

Sign up to answer this question »