Post History
I have decided to try design a band-pass filter with a cut-off frequency of 10kHz and bandwidth of 2 Hz. $$ \frac{1}{\sqrt{LC}} = 10001 \rightarrow LC = 1/100020001 sec^{2}$$ $$ \frac{R}{L} = 2...
#5: Post edited
by
Lorenzo Donati
·
2023-08-08T20:04:58Z (over 1 year ago)
Retagged.
#4: Post edited
by
MissMulan
·
2022-07-15T19:36:35Z (over 2 years ago)
- I have decided to try design a band-pass filter with a cut-off frequency of 10kHz and bandwidth of 2 Hz.
- 
$$ \frac{1}{\sqrt{LC}} = 10001 ightarrow LC = 1/100020001$$$$ \frac{R}{L} = 2$$$$ \frac{1}{RC} = 2$$- Here is what I have done but if I [plug the values to WolphramAlpha](https://www.wolframalpha.com/input?i=systems+of+equations+calculator&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation1%22%7D+-%3E%22x*y+%3D+1%2F100020001%22&assumption=%22FSelect%22+-%3E+%7B%7B%22SolveSystemOf3EquationsCalculator%22%7D%7D&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation2%22%7D+-%3E%22z%2Fy+%3D+2%22&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation3%22%7D+-%3E%221%2F%28z*x%29+%3D+2%22)
- it says it doesnt have any solutions.What am I doing wrong?
- I have decided to try design a band-pass filter with a cut-off frequency of 10kHz and bandwidth of 2 Hz.
- 
- $$ \frac{1}{\sqrt{LC}} = 10001 ightarrow LC = 1/100020001 sec^{2}$$
- $$ \frac{R}{L} = 2Hz$$
- $$ \frac{1}{RC} = 2Hz$$
- Here is what I have done but if I [plug the values to WolphramAlpha](https://www.wolframalpha.com/input?i=systems+of+equations+calculator&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation1%22%7D+-%3E%22x*y+%3D+1%2F100020001%22&assumption=%22FSelect%22+-%3E+%7B%7B%22SolveSystemOf3EquationsCalculator%22%7D%7D&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation2%22%7D+-%3E%22z%2Fy+%3D+2%22&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation3%22%7D+-%3E%221%2F%28z*x%29+%3D+2%22)
- it says it doesnt have any solutions.What am I doing wrong?
#3: Post edited
by
MissMulan
·
2022-07-15T18:09:26Z (over 2 years ago)
- I have decided to try design a band-pass filter with a cut-off frequency of 10kHz and bandwidth of 2 Hz.
- Here is what I have done but if I [plug the values to WolphramAlpha](https://www.wolframalpha.com/input?i=systems+of+equations+calculator&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation1%22%7D+-%3E%22x*y+%3D+1%2F100020001%22&assumption=%22FSelect%22+-%3E+%7B%7B%22SolveSystemOf3EquationsCalculator%22%7D%7D&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation2%22%7D+-%3E%22z%2Fy+%3D+2%22&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation3%22%7D+-%3E%221%2F%28z*x%29+%3D+2%22)
- it says it doesnt have any solutions.What am I doing wrong?
- I have decided to try design a band-pass filter with a cut-off frequency of 10kHz and bandwidth of 2 Hz.
- 
- $$ \frac{1}{\sqrt{LC}} = 10001 \rightarrow LC = 1/100020001$$
- $$ \frac{R}{L} = 2$$
- $$ \frac{1}{RC} = 2$$
- Here is what I have done but if I [plug the values to WolphramAlpha](https://www.wolframalpha.com/input?i=systems+of+equations+calculator&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation1%22%7D+-%3E%22x*y+%3D+1%2F100020001%22&assumption=%22FSelect%22+-%3E+%7B%7B%22SolveSystemOf3EquationsCalculator%22%7D%7D&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation2%22%7D+-%3E%22z%2Fy+%3D+2%22&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation3%22%7D+-%3E%221%2F%28z*x%29+%3D+2%22)
- it says it doesnt have any solutions.What am I doing wrong?
#2: Post edited
by
Olin Lathrop
·
2022-07-15T11:07:41Z (over 2 years ago)
- I have decided to try design a band-pass filter with a cut-off frequency of 10kHz and bandwidth of 2 Hz.
- Here is what I have done but if I [plug the values to WolphramAlpha](https://www.wolframalpha.com/input?i=systems+of+equations+calculator&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation1%22%7D+-%3E%22x*y+%3D+1%2F100020001%22&assumption=%22FSelect%22+-%3E+%7B%7B%22SolveSystemOf3EquationsCalculator%22%7D%7D&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation2%22%7D+-%3E%22z%2Fy+%3D+2%22&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation3%22%7D+-%3E%221%2F%28z*x%29+%3D+2%22)
- it says it doesnt have any solutions.What am I doing wrong?
- I have decided to try design a band-pass filter with a cut-off frequency of 10kHz and bandwidth of 2 Hz.
- Here is what I have done but if I [plug the values to WolphramAlpha](https://www.wolframalpha.com/input?i=systems+of+equations+calculator&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation1%22%7D+-%3E%22x*y+%3D+1%2F100020001%22&assumption=%22FSelect%22+-%3E+%7B%7B%22SolveSystemOf3EquationsCalculator%22%7D%7D&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation2%22%7D+-%3E%22z%2Fy+%3D+2%22&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation3%22%7D+-%3E%221%2F%28z*x%29+%3D+2%22)
- it says it doesnt have any solutions.What am I doing wrong?
#1: Initial revision
by
MissMulan
·
2022-07-14T23:15:22Z (over 2 years ago)
Band pass filter given cutoff frequency and bandwidth
I have decided to try design a band-pass filter with a cut-off frequency of 10kHz and bandwidth of 2 Hz.  Here is what I have done but if I [plug the values to WolphramAlpha](https://www.wolframalpha.com/input?i=systems+of+equations+calculator&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation1%22%7D+-%3E%22x*y+%3D+1%2F100020001%22&assumption=%22FSelect%22+-%3E+%7B%7B%22SolveSystemOf3EquationsCalculator%22%7D%7D&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation2%22%7D+-%3E%22z%2Fy+%3D+2%22&assumption=%7B%22F%22%2C+%22SolveSystemOf3EquationsCalculator%22%2C+%22equation3%22%7D+-%3E%221%2F%28z*x%29+%3D+2%22) it says it doesnt have any solutions.What am I doing wrong?