Activity for Carl‭

Type	On...	Excerpt	Status	Date
Comment	Post #288010	@TonyStewart thank you for the tips. The driven-right-leg technique is used to attenuate common mode residue by an additional factor K, after the differential signal has been sent through the inamp. I don't use a DRL-circuit in this design, because I post-process the data with a moving-average filter... (more)	—	about 1 year ago
Comment	Post #288010	@NickAlexeev Please post an answer to this question. You have peaked my interest, but writing this in the comment section is not the proper way I feel. Please explain what the addition of decoupling capacitors would do to the circuit. (more)	—	about 1 year ago
Comment	Post #288010	@NickAlexeev I have not used any decoupling capacitors in this design? Is that a mistake? If so, what would they do to my circuit? I don't quite understand what you mean with: *What's your analysis for patient isolation*. The patient and amplifier are isolated. The amplifier is powered through two 9... (more)	—	about 1 year ago
Comment	Post #288011	Hi Olin, thanks for this tip *This results in one clump of components around an opamp. Now you can move that whole clump around as needed. You can create several independent clumps like that* I struggled with this exact problem during the design. Also thanks for this one *This is the kind of thing th... (more)	—	about 1 year ago
Comment	Post #287952	I don't think I understand "an ECG signal is high impedance and this easily picks up line voltage E-fields". How can a signal impedance, and why does high impedance easily pick up radiation? (more)	—	about 1 year ago
Comment	Post #286114	Thank you very much for your clear answer. Also, thank you very much for that LT-Spice simulation. I encourage you to keep including these kind of simulations in your answers, because they inspire and teach the rest of us how to use LT-Spice! (more)	—	about 2 years ago
Comment	Post #286112	Hi Olin, thanks for your answer. I have edited the question and added some formulas given by my instructor and it looks like I used the wrong one. Using the formula for a buck-boost converter gives me d = 0.45... However, your answer is making me a little confused. Isn't buck-boost just as well-defi... (more)	—	about 2 years ago
Comment	Post #285820	@#52987 Yes exactly. Simplicity. I also think you should be able to upvote a comment, so that you can show that you agree with it, without having to post another comment just to say "I agree". And actually, I think it would be a good idea if you could get reputation from those "comment upvotes", if t... (more)	—	about 2 years ago
Comment	Post #286033	Thanks for your answer, Olin. This was exactly the kind of answer that I needed - no ambiguity what so ever. (more)	—	about 2 years ago
Comment	Post #286032	@#53072 Yeah this is homework. Should I include it in the title? The values are given by my instructor and are not found in a particular datasheet. (more)	—	about 2 years ago
Comment	Post #285820	@#53042 This post is not only about traffic but also about "Making a good first impression" which the site currently does not in my opinion. If you think the site looks better than SE you are delusional. Anyway thanks for the downvote. I'm glad I took the time to give constructive inputs only to rece... (more)	—	about 2 years ago
Comment	Post #285792	But it does violate the textbook. The Bode Plot on the left is a plot of \$H(j\omega)\$ which should be meaningless according to Lathi. But it is clearly not meaningless. (more)	—	about 2 years ago
Comment	Post #285786	Hi Olin thanks for your answer. Yes, I realize you need the system to be stable before you can start designing any form of controller. The problem I have is that there seems to be a disconnect between theory and real life. If I have a system with a pole in the RHP I can use the Nyquist Plot of \$H(j\... (more)	—	over 2 years ago
Comment	Post #284076	@#54107 The question and answers you have given are poorly presented and not easy to read/understand. The question is too specific to be useful for anyone other than yourself. And most importantly, the solution in your answer is incorrect! That is unacceptable and, honestly, embarassing. (more)	—	over 2 years ago
Comment	Post #284076	@#36396: Understood. But this doesn't seem like a question that matches the description you have given, in my opinion. (more)	—	over 2 years ago
Comment	Post #284076	Why are you answering your own questions? If you already know the answers why even post the question in the first place? (more)	—	over 2 years ago