Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

Comments on Confusion in operation of analog computer

Parent

Confusion in operation of analog computer

+1
−1

I am studying for a test in control systems and we have a practical part which is to program a analog computer.

Here is a picture of the analog computer:

Image alt text

The variable resistor is basically a voltage divider between VCC and VEE and you can change the output voltage by changing the position of the potentiometer.

Suppose we have this block diagram

Image alt text

We set the potentiometer to multiply the signal it sees by 0.4 then return to the input of a amplifier.Next to the potentiometer there are 3 pins the top pin and bottom pin are connected internally to VCC and VEE and the middle pin is the voltage division.When we are done setting the value of the potentiometer and connect the middle pin to the input of a amplifier and we are ready to measure the output voltage with a oscilloscope do we still keep the top and bottom pins plugged to power or not?Will I create a short if I keep the top and bottom pins plugged to power?

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.
Why should this post be closed?

2 comment threads

What rotary switch? (5 comments)
Block diagram is meaningless (2 comments)
Post
+0
−0

The two-terminal symbol for the attenuator comes from 3 pin potentiometer (pot.) referenced to 0V = "GND"

Image alt text

The summing amplifier is always inverting and gives you 3 options for gain which means internally it uses a 3 pin pot. to choose the gain for you based on the ratio of resistance from output to input side.

So when you choose an input like 10, does it make sense to choose another gain input in parallel? (no). You do need to chose an input since your block diagram shows no other input.

Since you have no input (=0) to a gain input(=-10) and feedback of 0.4 , your output should be 0 * (-10) * 0.4 = 0

Image alt text

What you show looks something like this.

Image alt text

Since your question is also confusing without expectations or purpose, perhaps you are trying to take a ratio between Vcc and Vee and then connect that scope measured value to the inverting sum amp.

like this: Image alt text

History
Why does this post require attention from curators or moderators?
You might want to add some details to your flag.

2 comment threads

Note: I just chose a small voltage with gain of -10 (1 comment)
Comments (2 comments)
Note: I just chose a small voltage with gain of -10
TonyStewart‭ wrote over 1 year ago

Note: I just chose a small voltage with gain of -10