Activity for MissMulan
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Question | — |
Capacitor in 2nd stage of opamp Inside a op-amp after the stage where the differential signal is converted to single ended , there is further amplification of the DC signal.For AC signals there is a capacitor parallel to the transistor.Why is it there? (more) |
— | over 3 years ago |
| Comment | Post #282585 |
Ok it is ready for reopening (more) |
— | over 3 years ago |
| Edit | Post #282585 |
Post edited: |
— | over 3 years ago |
| Edit | Post #282585 |
Post edited: |
— | over 3 years ago |
| Edit | Post #282585 | Initial revision | — | over 3 years ago |
| Question | — |
Critically damped oscillation issue I have a question about this circuit:(critically damped oscillation) SeeMe For a critically damped oscillation for a series RLC circuit the equation of current has this form I(t)=D1te^(-at)+D2e^(-at) where D2 =I(0+) and D1-aD2 = dI(0+)/dt=VL/L. Due to L1 :I(0)=I(0+)=0A and by applying KV... (more) |
— | over 3 years ago |
| Comment | Post #282434 |
How are the equations derived?I didnt get it. (more) |
— | over 3 years ago |
| Comment | Post #282363 |
Yes and Vout cant become less than Vin-.How can we fix this? (more) |
— | over 3 years ago |
| Comment | Post #282363 |
Excellent answer!But I have done some experiments on falstad and every time Vin+ becomes less than Vin- Q2 is driven to saturation and if Vin+ becomes more than Vin- Q4 is driven to saturation.Is that normal? (more) |
— | over 3 years ago |
| Edit | Post #282361 | Initial revision | — | over 3 years ago |
| Question | — |
Help with differential to single ended voltage converter Hello I don't understand how this differential to single-ended voltage converter can work. What I don't understand is why we place a current mirror(a current mirror copies the current flowing through one transistor to another transistor) and how is the output voltage affected by the input volt... (more) |
— | over 3 years ago |
| Edit | Post #282262 | Initial revision | — | over 3 years ago |
| Question | — |
Unexpected phase shift in results I find the current flowing through the capacitor $$\begin{align} I{C1}(t)&=\dfrac{\mathrm{d}}{\mathrm{d}t}\left[V1(t)-I{C1}(t)R1\right] \\\\ {}&= \dfrac{\mathrm{d}}{\mathrm{d}t}\left[\sin(t)-I{C1}(t)\right] \end{align}$$ and by solving this differential equation we get $$I{C1}(t) = \dfrac... (more) |
— | over 3 years ago |
| Edit | Post #282180 | Initial revision | — | over 3 years ago |
| Question | — |
Current and voltage in AC circuits without impedance How can we find the equation of current and voltage of a capacitor circuit if the input voltage is AC without using the impedance formula Xc = -jωC?. SeeMe We have for homework to find the equation of current of the circuit and the equation of voltage of the capacitor assuming we just connected... (more) |
— | over 3 years ago |