Activity for MissMulan
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Question | — |
Diode like a frequency mixer Based on this paper on Wiki a diode can be described as a frequency mixer due to the exponential relationship between current and voltage.What I don't get from which point to which point do we measure the voltage with the different frequency(or whatever)? So if we connect a oscilloscope to the cir... (more) |
— | about 3 years ago |
| Edit | Post #283585 | Initial revision | — | over 3 years ago |
| Question | — |
$Q$ and $\overline{Q}$ in bistable multivibrator In this bistable multivibrator which is $Q$ and which is $\overline{Q}$? (more) |
— | over 3 years ago |
| Comment | Post #283436 |
Suppose we have a transistor connected in series with a magnetic tunnel junction.1st case:the output voltage is low(the transistor is off) (0V)this represents the case of no charge state.2nd case:the transistor is on and the 2 layers of ferromagnetic materials which create the magnetic junction, hav... (more) |
— | over 3 years ago |
| Edit | Post #283436 |
Post edited: |
— | over 3 years ago |
| Comment | Post #283436 |
@#53072iot if the charge state is 0, then we dont hav to worry about the spin state.Spintronics provide us with 3 available states unlike electronics which provides us with only 2 states. (more) |
— | over 3 years ago |
| Edit | Post #283436 | Initial revision | — | over 3 years ago |
| Answer | — |
A: A signal with one mode or with three or more modes > The term "Discrete" uses to describe a signal with two modes. Wrong. Discrete means it can only take some values , not all values. I suspect by 'modes' you mean # of possible outputs. If we have a system which outputs only have 1 possible output then what would be the point of that system?... (more) |
— | over 3 years ago |
| Edit | Post #283369 | Initial revision | — | over 3 years ago |
| Question | — |
Tunnel current equation The current through the tunnel diode is: hi where $I{f}$ is the current from the Shockley diode equation and $I{tunnel}$ is the tunnel current. Is there an expression for the tunnel current or is it found 'experimentally'?[]() (more) |
— | over 3 years ago |
| Comment | Post #283331 |
So a DC blocking capacitor to not allow any current flowing from the DC source to the AC source? (more) |
— | over 3 years ago |
| Edit | Post #283325 | Initial revision | — | over 3 years ago |
| Question | — |
Adding resistance to varactor circuit If we a varactor and we want to control let's say the resonant frequency of the circuit ,in my schematic we must add R1 correct?Else we create a low resistance path for current to flow not through the varactor so the "AC circuit" gets distorted from the "DC circuit". hi So by changing the val... (more) |
— | over 3 years ago |
| Edit | Post #283249 | Initial revision | — | over 3 years ago |
| Answer | — |
A: 3+3 doesn’t show 6 The correct 1 bit full adder is this:hi (more) |
— | over 3 years ago |
| Edit | Post #283244 | Initial revision | — | over 3 years ago |
| Question | — |
3+3 doesn’t show 6 I have a problem which I don’t understand how to solve. I have this 2-bit adder, but when I select A1AO to be (11)2 3 and B1BO to be (11)2 3 and run it on Logisim it doesn’t show me 6. Instead it shows me 4. How can I fix it? hi (more) |
— | over 3 years ago |
| Comment | Post #283207 |
I know that.Is there a way to use the comparator(s) as 'effeciently' as possible(no loops,storage of value ) and make a simple logic digital circuit? (more) |
— | over 3 years ago |
| Edit | Post #283206 | Initial revision | — | over 3 years ago |
| Question | — |
Division of binary numbers logic circuit If we want to divide two numbers I have problem implementing this logic.I am posting 1 images with 2 different steps to the solution. In example a) the most significant digits of the divident >= divisor we subtract the divisor from those 2 digits. hello In b)the most significant digits of th... (more) |
— | over 3 years ago |
| Comment | Post #283172 |
I cant understand which pins to connect with which pins. (more) |
— | over 3 years ago |
| Comment | Post #283170 |
I think multiplication can be done without bit shifting just by using full adders and taking advantage of the vertical addition of 2 binary numbers.However we are missing the point here.Is there a similar 'function' which does the same for vertical subtraction? (more) |
— | over 3 years ago |
| Comment | Post #283170 |
I have heard that for division of binary numbers you need to understand well subtraction so just like we can multiply 2 numbers with full adders maybe we can divide 2 numbers with full subtractors thats why I want to know how to edo subtraction using full subtractors. (more) |
— | over 3 years ago |
| Comment | Post #283172 |
I know how to make a full subtractor i just dont know how to connect multiple of them in order to make subtraction of 2 binary numbers with more than 1 bit (more) |
— | over 3 years ago |
| Edit | Post #283170 | Initial revision | — | over 3 years ago |
| Question | — |
2 bit subtractor using full subtractor Can we make a n-bit subtractor using full subtractors or if we want do subtract one binary from another we must use full adders and use the complement of the 2nd number to do the subtraction? I have only found examples which we use the complement of the second number and using full adders if it is... (more) |
— | over 3 years ago |
| Edit | Post #282738 | Initial revision | — | over 3 years ago |
| Question | — |
Electric circuit with antenna Moderator's note: This is getting ridiculous. You keep posting these drawings that are barely legible. The scribbling is bad enough, but the uncropped images are unacceptable. The image you originally posted below was 2500 x 1667 pixels, even though the drawing occupied only a small piece of th... (more) |
— | over 3 years ago |
| Edit | Post #282733 | Initial revision | — | over 3 years ago |
| Question | — |
JFET equation of current Is this equation valid only when a JFET in saturation mode , correct? because in the ohmic region the JFET acts like a voltage controlled resistor and increase in VDS increases the resistance of the JFET. Hi (more) |
— | over 3 years ago |
| Edit | Post #282711 |
Post edited: |
— | over 3 years ago |
| Edit | Post #282711 | Initial revision | — | over 3 years ago |
| Question | — |
Diodes used in mixers Suppose we have this circuit which is supposed to be an unbalanced frequency mixer. But how does the diode generate a signal with new frequencies at the output? Hi (more) |
— | over 3 years ago |
| Comment | Post #282710 |
An input signal can have noise and usually the noise is an AC signal so if im receiving dc signal+noise i would like to remove the noise. (more) |
— | over 3 years ago |
| Edit | Post #282709 | Initial revision | — | over 3 years ago |
| Question | — |
Extract DC component of mixed signal How can we extract a DC signal from a mixed signal?If we want to extract the AC component of a signal we can use a blocking capacitor to remove any DC offset but how do we achieve the opposite?Can we use a band-pass filter? (more) |
— | over 3 years ago |
| Edit | Post #282690 |
Post edited: |
— | over 3 years ago |
| Edit | Post #282690 |
Post edited: |
— | over 3 years ago |
| Edit | Post #282690 | Initial revision | — | over 3 years ago |
| Question | — |
MOSFET differential to single ended converter intuition How does the differential to single ended converter work? In order for the circuit to work, Q1 and Q3 must be in the saturation region and depending on the voltage inputs, one of Q2 and Q4 will be in the ohmic region and one will be in the saturation region. I understand that IQ1 is copied to (... (more) |
— | over 3 years ago |
| Comment | Post #282672 |
Yeah for you it may be easy I have tried learning MathJax and couldn't (more) |
— | over 3 years ago |
| Edit | Post #282671 |
Post edited: |
— | over 3 years ago |
| Comment | Post #282672 |
@#36396 I dont know how to use LaTeX and I used one of the online editors I found.I tried to find an online editor which didnt do that but I couldnt find one. (more) |
— | over 3 years ago |
| Edit | Post #282671 | Initial revision | — | over 3 years ago |
| Question | — |
Voltage of tank circuit is invalid In a previous question we found that for a critically damped oscillation: $$ I(t) = 2 t e^{-0.5 t} $$ But if we integrate to find the voltage through the capacitor: $$ V{CO} + \frac{1}{C} \cdot \int0^t{I(t)}dt $$ the integral is always a positive value which doesn't make any sens... (more) |
— | over 3 years ago |
| Comment | Post #282635 |
Thanks I understand now/ (more) |
— | over 3 years ago |
| Comment | Post #282635 |
Sorry what you write doesnt make any sense to me.From KVL Vs=Vc+Vl+IR , I=0 and Vs=0 (no battery connected to the circuit)->VC=-VL->VL=-2V. (more) |
— | over 3 years ago |
| Comment | Post #282635 |
I still dont get it VL=-VC = -2V. (more) |
— | over 3 years ago |
| Comment | Post #282627 |
But the opamp can correctly function without the capacitor,correct? (more) |
— | over 3 years ago |
| Edit | Post #282624 | Initial revision | — | over 3 years ago |