Activity for Volpinaâ€
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Comment | Post #288390 |
If the baud rate is very big then even small differences are very important. (more) |
— | 11 months ago |
| Comment | Post #288233 |
@#58091 The output of a oscillator is AC by definition so I dont think a capacitor will help.I could be wrong tho. (more) |
— | 12 months ago |
| Comment | Post #288222 |
Unfortunately the CE5a is a very old machine and not very popular(it is mostly used for educational purposes).Sadly I didnt find its datasheet in the Internet. (more) |
— | 12 months ago |
| Comment | Post #288222 |
Ah i thought because you rotated it to change values is a rotary switch ,I have never seen a potentiometer in the form as shown in the picture. (more) |
— | 12 months ago |
| Comment | Post #288222 |
Well how do you call the switch which sets the output voltage of the variable resistor?Isnt that a rotary switch? (more) |
— | 12 months ago |
| Comment | Post #288225 |
Yes you are correct that the output will always be 0 bcs I havent provided a input non-zero signal to my amplifier.So assume I apply a input square wave signal from a frequency generator and I apply it to the x10 multiplier pin then do I need to connect the top and bottom pins of the rotary switch t... (more) |
— | 12 months ago |
| Comment | Post #288159 |
@#52987 I dont know thats why I am asking. (more) |
— | 12 months ago |
| Comment | Post #288153 |
The image of the equivalent circuit of a transformer and the diagrams of the operation of a transformer under different loads dont come from the same source so the labels dont match.
A inductive or a capacitive load isnt a pure inductor or a pure capacitor its a combination of a series resistance wi... (more) |
— | 12 months ago |
| Comment | Post #288153 |
Hmm there isnt a explanatory text around them ,the diagrams come from the slides of my college professor and he just showed us the diagrams without explaining what the quantities on the diagrams are.I am interested in knowing what they are. (more) |
— | 12 months ago |
| Comment | Post #288118 |
The zener connected in the negative feedback loop regulates the voltage of the load anyway.I dont see the reason for that many zener diodes... (more) |
— | about 1 year ago |
| Comment | Post #288107 |
@Lundin My line of thinking was that by adding a big capacitor parallel to the DC voltage source , any noise current due to the thermal noise voltage of the resistors wont flow inside the voltage source which may damage it. (more) |
— | about 1 year ago |