Activity for Olin Lathropâ€
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Comment | Post #285325 |
Define your terms. The 3-phase systems I've seen are all either Y or Delta. I've never encountered anything called "Y-Y" or "D-D". Explain what those are. (more) |
— | almost 3 years ago |
| Edit | Post #285248 | Initial revision | — | almost 3 years ago |
| Answer | — |
A: Bandwidth of serial signal You have to decide what you really mean by "bandwidth". The analog bandwidth of the channel is quite different from the bit rate, which is different from the effective bit rate of the actual transferred data. Let's take the common UART protocol of 9600 8-N-1 (9600 baud, 8 data bits, no parity, on... (more) |
— | almost 3 years ago |
| Comment | Post #285242 |
I had to look at it a bit to realize that your X axis is negative time. That's unconventional. Worse yet, it's not even labeled. (more) |
— | almost 3 years ago |
| Comment | Post #285198 |
The passive sensors connected to my circuit will be in a fuel tank, but the circuit itself won't be in a hazardous location. As I understand it, the focus is then on making sure that whatever voltage and current is delivered to the sensor can't ignite volatile gasses. That means a maximum voltage a... (more) |
— | almost 3 years ago |
| Comment | Post #285201 |
Thanks. This is exactly the type of feedback I am looking for! I was trying to show that the current coming out of the flyback converter can't exceed a certain value. But, it makes a lot more sense to just put a fuse there and be done with it (Duh! Seems obvious now that you point it out). As I u... (more) |
— | almost 3 years ago |
| Comment | Post #285198 |
It seems you are talking about circuitry that is actually in the hazardous environment. What I'm designing is an "associated apparatus". It will not itself be in the hazardous location, but will connect to passive sensors that will be. As far as I am aware, the current and temperature limitations ... (more) |
— | almost 3 years ago |
| Edit | Post #285186 |
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— | almost 3 years ago |
| Comment | Post #285170 |
@Monica: That's hard to guess. I wouldn't have thought of capacitance multipliers until I saw that paper, for example. I did write a few self-answered question early-on that I knew from elsewhere were common topics of questions. That was before we had the Papers category. I've got several ideas f... (more) |
— | almost 3 years ago |
| Edit | Post #285186 | Initial revision | — | almost 3 years ago |
| Question | — |
Flyback transformer with Intrinsic Safety I have no experience designing for Intrinsic Safety (IS), but need to do that now. I have read thru IEC 60079-11, which seems to be the relevant standard for my purposes. The board I need to design will be an "associated apparatus" in IS terms. That means the board won't be in a hazardous locati... (more) |
— | almost 3 years ago |
| Comment | Post #285170 |
@Monica: If people are finding that post by searching for "capacitance multiplier", then things are working well. I think what's going on is that there isn't a lot about capacitance multipliers out there, so the search engines find this post. That's actually a great result. (more) |
— | almost 3 years ago |
| Comment | Post #285170 |
@Monica: I don't see anything particularly special, other then a well written post that does a good job of covering its topic. Being a fairly long post, it contains a bunch of search-fodder jargon words. Maybe that helps. Maybe the topic is covered in some courses, and this post matches all the ty... (more) |
— | almost 3 years ago |
| Edit | Post #285171 |
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— | almost 3 years ago |
| Edit | Post #285171 | Initial revision | — | almost 3 years ago |
| Answer | — |
A: How to treat data communication questions? I agree that the particular question was correctly closed. Questions about protocol stacks aren't necessarily off topic. However, this one was because nothing about it had anything to do with electronics or low level embedded systems. Where should I ask it then? I don't know. That's not ... (more) |
— | almost 3 years ago |
| Edit | Post #285106 | Initial revision | — | almost 3 years ago |
| Answer | — |
A: How can we grow this community? Another thing that would be helpful is to get the existing users to participate more. Upvote good questions when you see them! For example, the question "208VAC triple-phase to single-phase conversion" was posted 2 days ago. It is on topic, well asked, well written, and appears to be a genuine... (more) |
— | almost 3 years ago |
| Edit | Post #285084 |
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— | almost 3 years ago |
| Edit | Post #285084 | Initial revision | — | almost 3 years ago |
| Answer | — |
A: Do we need tags for supply voltages? I agree that "208VAC" and "230VAC" are too specific to be useful. I tried to edit the post to remove them. There is apparently a bug in the system. While I removed both tags from the post, one of them still shows. However, when I go to edit the post again, that tag is not there, so I can't remo... (more) |
— | almost 3 years ago |
| Edit | Post #285070 |
Post edited: Removed inappropriate tags |
— | almost 3 years ago |
| Edit | Post #285078 | Initial revision | — | almost 3 years ago |
| Answer | — |
A: 208VAC triple-phase to single-phase conversion You need a real transformer that converts 208 V to 230 V, so a ratio of 1:1.11. This can not be an auto-transformer because you need isolation between the primary and secondary. That is because you will ground one side of the output, but neither input can be connected to ground. Alternatively, y... (more) |
— | almost 3 years ago |
| Edit | Post #285059 | Initial revision | — | almost 3 years ago |
| Answer | — |
A: How can we grow this community? One way we can grow this community is to have existing users here mention the site at relevant gatherings. Unfortunately, those have been non-existent or virtual due to covid. Passing on a recommendation about a Q&A site is the kind of side-conversation that doesn't happen as much in virtual meetin... (more) |
— | almost 3 years ago |
| Comment | Post #284995 |
This doesn't answer the question of "how" at all. It's merely another way to model the non-linear behavior of a diode (or any two-terminal device). You could just as well have said it's a current source that is a non-linear function of voltage, or a voltage source that is a non-linear function of t... (more) |
— | almost 3 years ago |
| Edit | Post #284984 | Initial revision | — | almost 3 years ago |
| Answer | — |
A: Asynchronous connection question How does the receiver understand the end bits? It doesn't. The purpose of stop bits (what you seem to be calling "end bits") is to leave a guaranteed gap before the next start bit. The leading edges of start bits are always idle to non-idle transitions. The line must therefore always be at id... (more) |
— | almost 3 years ago |
| Comment | Post #284936 |
I understand the units are mislabeled in the diagram, which is not under your control. However, you continued the sloppiness with units in your own text. You should have written (1 m)/c instead of 1/c. Units matter. (more) |
— | almost 3 years ago |
| Edit | Post #284936 |
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— | almost 3 years ago |
| Edit | Post #284936 |
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— | almost 3 years ago |
| Edit | Post #284936 | Initial revision | — | about 3 years ago |
| Answer | — |
A: How long does it take for energy to propagate in a circuit? Is the answer of 1/c seconds correct It can't possibly be. The question is looking for a time value. "C" is a speed, which has units of distance/time. "1/c" therefore has units of time/distance. In this case, 1 is 1 meter "1" is never one meter. "1 m" or "1 meter" is one meter. Ad... (more) |
— | about 3 years ago |
| Edit | Post #284896 | Initial revision | — | about 3 years ago |
| Answer | — |
A: Flyback converter design i dont know how to control two outputs with a single control loop Neither does anyone else. Your output has two degrees of freedom, and your control input only one. That's a fundamental problem you can't fix with any amount of clever design. Physics can be annoying like that. However, you ca... (more) |
— | about 3 years ago |
| Edit | Post #284839 | Initial revision | — | about 3 years ago |
| Answer | — |
A: Resistance of digital ampmeter What you linked to is more of a user's manual than a datasheet. Particularly for more consumer-oriented meters, this spec may not be explicitly available. However, you can easily measure it. Use an ohmmeter to measure the resistance of the ammeter. You should see the ammeter report a small curr... (more) |
— | about 3 years ago |
| Edit | Post #284776 | Initial revision | — | about 3 years ago |
| Answer | — |
A: What is sacrificed when buying cheaper oscilloscope probes (of same BW/cap/R/gain) Some issues: Physical robustness. Some probes just are built better than others. How well does the clip pop off? How well does it stay on when you don't want it to pop off? How solid is the hook at the end of the clip? Is the hook sized well? When you remove the clip, how sharp but yet s... (more) |
— | about 3 years ago |
| Edit | Post #284543 |
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— | about 3 years ago |
| Edit | Post #284543 |
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— | about 3 years ago |
| Edit | Post #284636 |
Post edited: Moved "answer" to here since it was actually more information about the question. |
— | about 3 years ago |
| Edit | Post #284637 | Initial revision | — | about 3 years ago |
| Answer | — |
A: Low-frequency PWM-controlled Mosfet heater circuit Your main complaint seems to be that the 24 V power rail sags 800 mV when the heater is on. Three responses pop to mind: So what? It probably isn't anyway. What did you expect? #1: So what? I don't see any harm in the 24 V supply actually being 23.2 V when the heater is on. Unless ... (more) |
— | about 3 years ago |
| Edit | Post #284626 |
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— | about 3 years ago |
| Edit | Post #284626 |
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— | about 3 years ago |
| Edit | Post #284626 | Initial revision | — | about 3 years ago |
| Answer | — |
A: MOSFET not turning completely off To protect against future changes and to provide something slightly more readable, here is your schematic: There is no immediately obvious reason the FET should blow, but there are a number of issues here: If "VIN17V" is to be believed, and the voltage really is 17 V, then that is way too m... (more) |
— | about 3 years ago |
| Comment | Post #284538 |
You can think of it that way. With the base voltage held constant, the transistor itself produces more emitter current when the emitter voltage drops. (more) |
— | about 3 years ago |