Activity for Olin Lathrop
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Edit | Post #287211 |
Post edited: |
— | over 1 year ago |
| Edit | Post #287211 | Initial revision | — | over 1 year ago |
| Answer | — |
A: Low-pass filter after the output DAC in CD players I don't know what the book has in mind, but your first point is the main reason I would want to filter out the high frequencies with passive analog components. Low noise and low distortion are important in audio. It makes a real difference when the amplifier has to still have low noise and distor... (more) |
— | over 1 year ago |
| Edit | Post #287197 | Initial revision | — | over 1 year ago |
| Answer | — |
A: Deriving resistor values for a taper pad attenuator I'm thinking out loud here and haven't solved this yet. This answer is logging my process as I try to solve the problem. It may very well result in the same long-winded process you went thru. Nothing shrewd or insightful is promised. There are three unknowns (R1, R2, R3), and there are fortunat... (more) |
— | over 1 year ago |
| Comment | Post #287196 |
Are Rin and Rl defined with the other end connected? For example, Rin must be right when a load is connected to the output, but can be different when the output is left open. The same question applies to the output impedance whether the input is connected or left open. I think you mean both input ... (more) |
— | over 1 year ago |
| Edit | Post #287029 |
Post edited: |
— | over 1 year ago |
| Comment | Post #287027 |
A Siemen is just 1/Ohm. Ohms is a measure of *resistance*, not resistivity. The reciprocal of Ohms is neither. An Ohm times a length is a measure of resistivity. Conversely, 1/(Ohm-length) is a measure of conductivity. Siemens must be divided by a length to become conductivity. µS/furlong is a ... (more) |
— | over 1 year ago |
| Edit | Post #287029 | Initial revision | — | over 1 year ago |
| Answer | — |
A: pH Electrode Buffer - Offset when solution grounded It seems you have ground loops, and possibly having multiple ground connections shorting out your signals. Your hand-sketched diagram is a good start, but you need to show all the ground connections. The scope is presumably grounded via its ground lug that plugs into the electrical outlet. Let's... (more) |
— | over 1 year ago |
| Comment | Post #287027 |
µS is not a measure of conductivity. Fix your units. (more) |
— | over 1 year ago |
| Comment | Post #286988 |
Close reason: Raw homework dump. Read the rules. (more) |
— | over 1 year ago |
| Edit | Post #286988 | Question closed | — | over 1 year ago |
| Edit | Post #286952 |
Post edited: |
— | over 1 year ago |
| Edit | Post #286952 | Initial revision | — | over 1 year ago |
| Answer | — |
A: Technique to reset pulse transformer core quickly Note that open-circuiting an inductor "resets" the magnetic field instantly. The downside is that this also generates infinite voltage for that infinitely small time. Infinite voltage is obviously bad, but you should easily be able to tolerate "high enough" voltage relative to your 5 V drive. Us... (more) |
— | over 1 year ago |
| Edit | Post #286946 |
Post edited: |
— | over 1 year ago |
| Edit | Post #286946 | Initial revision | — | over 1 year ago |
| Answer | — |
A: Power amplifier for remote controller According to the datasheet that Andy linked to, the chip can be configured for 0 dBm output. With the proper antenna, that is probably good enough for 20 m, but you'll have to test it yourself to know for sure. If your environment is noisy, or there are obstructions causing path loss or multi-path ... (more) |
— | over 1 year ago |
| Edit | Post #286938 | Initial revision | — | over 1 year ago |
| Answer | — |
A: Can confusing the plugs for earphones and microphones do any damage? Yes, plugging a microphone into a headphone output could possibly damage the microphone. Microphones are designed to work on tiny vibrations and tiny currents. A dynamic microphone will work backwards as a speaker, but at very low power. In any case, across all the various combinations of ouputs... (more) |
— | over 1 year ago |
| Comment | Post #286862 |
I think you meant to say something else in the first bullet point. 180° phase shift already is an inversion. "180° inversion" doesn't make any sense either. (more) |
— | over 1 year ago |
| Edit | Post #286864 | Initial revision | — | over 1 year ago |
| Answer | — |
A: Circuit which create ac sine wave from dc pulsed signal There is no "simple" circuit that does the reverse conversion of what a full wave bridge does on a sine wave. However, it is possible to get there from here. Most of what you are asking about is an inverter. That's the reverse of a DC power supply. You put DC in, and AC power comes out. Put ... (more) |
— | over 1 year ago |
| Comment | Post #286850 |
This device is basically a 32-channel ohmmeter. It needs to measure about 75 Ω to 40 kΩ to within a couple of ohms. Zener leakage is too unpredictable and temperature-dependent to calibrate out.
In the mean time, I used a circuit like what Andy suggested. The overall device is worki... (more) |
— | over 1 year ago |
| Comment | Post #286836 |
Closed. You were warned before. (more) |
— | over 1 year ago |
| Edit | Post #286836 | Question closed | — | over 1 year ago |
| Edit | Post #286841 | Initial revision | — | over 1 year ago |
| Answer | — |
A: What are the key programming skills for an embedded systems engineer? First, we have to clarify what you really mean by "embedded systems". There are many systems where something that is logically a PC is embedded. There is a whole industry around "single board computers" (SBCs). For a few 100 dollars, you can get a board that runs Windows or Linux, but is inten... (more) |
— | over 1 year ago |
| Edit | Post #286793 |
Post edited: |
— | almost 2 years ago |
| Comment | Post #286793 |
I was referring to the opamp by itself. An ideal opamp in this case will have zero output impedance. I didn't mean that the zero output impedance is ideal for the rest of the circuit. In fact, I even pointed out how the inductor across the output is pointless in this circuit because the output of ... (more) |
— | almost 2 years ago |
| Comment | Post #286793 |
Oops. I meant to say high pass. Fixed. It should be doable without the resistor on the output of the oscillator. The right LC network can use the fixed input impedance of the inverting amplifier to control Q.
I'm not sure the OP is ready for these details yet. I haven't seen any evidence that ... (more) |
— | almost 2 years ago |
| Edit | Post #286793 |
Post edited: |
— | almost 2 years ago |
| Comment | Post #286792 |
You have been told this before. Use junction dots to show what intersecting schematic lines connect and which don't. For example, in the right diagram we can't tell whether only the bottom of L1 is connected to ground, or whether R1 and L2 also are. This is your last warning. (more) |
— | almost 2 years ago |
| Edit | Post #286793 | Initial revision | — | almost 2 years ago |
| Answer | — |
A: Op Amp Hartley oscillator You are asking how to analyze this circuit: Forget about what you think it should be called. Before attempting to model specific aspects, first try to understand the circuit. The opamp provides gain of -R2/R1. For an ideal opamp, the output of the opamp has zero impedance in this circuit.... (more) |
— | almost 2 years ago |
| Comment | Post #286766 |
In Eagle you can make generic symbols that can be customized with "attributes", which are sortof like environment variables that are set in the device. The device is what binds a symbol to one or more packages, and is a container for higher level information above the packages and symbols. Maybe Al... (more) |
— | almost 2 years ago |
| Comment | Post #286745 |
Still no schematic. (more) |
— | almost 2 years ago |
| Comment | Post #286745 |
You were warned several times about posting sloppy writing that you clearly didn't bother to proofread. I lost track what that runon sentence is about before even getting to the end. No, I'm not going to read it five times to figure out what it's asking, and neither should the volunteers here eithe... (more) |
— | almost 2 years ago |
| Edit | Post #286745 | Question closed | — | almost 2 years ago |
| Edit | Post #286743 | Initial revision | — | almost 2 years ago |
| Answer | — |
A: Small signal analysis of BJT in saturation region A resistor is not a good model for a saturated BJT. According to your graphs it is, but those are simplified. There isn't really a single slope for all base currents as your graph shows. Even if you can approximate some region of interest with a fixed slope, that slope will vary quite a bit betwee... (more) |
— | almost 2 years ago |
| Comment | Post #286730 |
Don't tell me here. Put that in the question so everyone can see what is really going on. (more) |
— | almost 2 years ago |
| Comment | Post #286730 |
I'm not going to answer until you explain the larger problem this fits into. You have abused the volunteers here with very unusual requirements that you simply dreamed up, and that would not present themselves in a real world situation. Either explain the real-world problem you are facing, or menti... (more) |
— | almost 2 years ago |
| Comment | Post #286721 |
You fixed the image, but you haven't fixed the other problems I mentioned above. And, you added new problems. You have various combinations of inductance and capacitance being equated to dimensionless quantities. It doesn't take special electronics knowledge to get units right. Sloppiness is not ... (more) |
— | almost 2 years ago |
| Comment | Post #286721 |
I've told you before, the last time only three days ago, to post images that we can actually read. Not only did you not fix that one, but now you're here doing it again. This time I deleted it since there is no point in having unreadable images here. I also downvoted due to the gross sloppiness. ... (more) |
— | almost 2 years ago |
| Edit | Post #286721 |
Post edited: |
— | almost 2 years ago |
| Edit | Post #286723 | Initial revision | — | almost 2 years ago |
| Answer | — |
A: Band pass filter given cutoff frequency and bandwidth I have decided to try design a band-pass filter with a cut-off frequency of 10kHz and bandwidth of 2 Hz. It's "10 kHz", not "10kHz". There needs to be a space between the number and the unit. NIST has a good document about this. Proper use of units and their presentation matter. I've sai... (more) |
— | almost 2 years ago |
| Comment | Post #286705 |
Your original diagrams were already too small to read easily. Your new diagrams are worse. You really should be able to see that for yourself. The problem seems to be that you are trying to cram too much stuff into pictures horizontally. Keep in mind that any picture you post will be resized to a... (more) |
— | almost 2 years ago |