Activity for Andy aka
| Type | On... | Excerpt | Status | Date |
|---|---|---|---|---|
| Comment | Post #287532 |
What, you want examples of crucibles so that you can make your coil? (more) |
— | over 1 year ago |
| Comment | Post #287480 |
You say radiation in your title but, you mention cables in the body of your question so, which is it; RF radiated emissions or cable-conducted emissions? (more) |
— | over 1 year ago |
| Comment | Post #287434 |
You said "voltage 18v" but your circuit shows 5 volts. You need to explain what you mean. (more) |
— | over 1 year ago |
| Comment | Post #287302 |
The whole basis of this question is something apparently misunderstood in college and, is unable to be confirmed by Miss Mulan. It should now be closed. (more) |
— | over 1 year ago |
| Comment | Post #287302 |
Your first assertion about S needs to be linked to where you read that. The information in your text book needs to be shown as a picture so it can be double checked. (more) |
— | over 1 year ago |
| Edit | Post #287296 |
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| Edit | Post #287296 |
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| Edit | Post #287296 | Initial revision | — | over 1 year ago |
| Answer | — |
A: Energy harvesting from non-invasive current sense transformer Most of the energy produced by the CT windings is being wasted in the internal burden resistor. See this data sheet to see what I mean. I calculate that it has a 60 Ω burden resistor and, at full primary current (30 amps) it wastes nearly 17 mW of power. At 3 amps, it wastes only 167 μW. ... (more) |
— | over 1 year ago |
| Edit | Post #287257 |
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| Edit | Post #287257 |
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| Comment | Post #287257 |
I have no idea why you made this comment Tony. (more) |
— | over 1 year ago |
| Edit | Post #287263 |
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| Edit | Post #287263 |
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| Edit | Post #287263 |
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| Edit | Post #287263 |
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| Edit | Post #287263 |
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| Edit | Post #287263 | Initial revision | — | over 1 year ago |
| Answer | — |
A: Ceramic filter vs ceramic resonator The Murata part you have chosen as a replacement is unsuitable. Its only application is to cheaply replace crystals in oscillators and, as such, it will have a profoundly tight bandwidth (maybe less than 100 Hz or so) whereas the original filter you linked has a 20 dB bandwidth of 750 kHz (as per the... (more) |
— | over 1 year ago |
| Comment | Post #287262 |
Try directly connecting the lines without any hinderance and see what the result is. Proceed with that situation until its fixed then, move onto coupling via the power rails. (more) |
— | over 1 year ago |
| Comment | Post #287262 |
Try a direct communication to rule out DC filters affecting the comms. (more) |
— | over 1 year ago |
| Comment | Post #287262 |
Data sheet links needed for the ceramic parts. Circuit diagram of the low pass-filters on the DC bus needed. Have you tried connecting two units directly to see that they work on an exclusive connection? (more) |
— | over 1 year ago |
| Edit | Post #287257 |
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| Edit | Post #287257 |
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| Edit | Post #287257 |
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| Comment | Post #287257 |
It's a dc output that is unspecified but about 1 kW. The input supply is around +/-250 volts DC. There is no 3-phase connection. Output is variable between 300 volts and 600 volts. Thanks for asking. (more) |
— | over 1 year ago |
| Comment | Post #287257 |
No, I just don't want to use a transformer. Sure there's current sensing and voltage sensing and specialty drivers but these are beyond what I'm asking about. Basically, how would you configure the single ended power supply version to work with split input supplies is what I'm asking. (more) |
— | over 1 year ago |
| Edit | Post #287257 |
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| Comment | Post #287258 |
+1 for the obvious work round. I'm going to edit my question (with full respect to your answer) asking for non-transformer solutions. (more) |
— | over 1 year ago |
| Edit | Post #287257 |
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| Edit | Post #287257 | Initial revision | — | over 1 year ago |
| Question | — |
Buck-boost converter fed from split input supply I have recently finished designing a buck-boost converter for a job that uses a split (+/-) input power supply. Load power is taken equally from both positive and negative input supplies and, the load is connected to 0 volts (mid-rail of the split input supply). $$$$ For a single rail supply,... (more) |
— | over 1 year ago |
| Comment | Post #287232 |
Not trying to be picky here; just trying to clarify when you say \$R_{23}\$ is the resistance at point X seen from the input, wouldn't it be easier on the eyes if you said it's the resistance at point x with the input disconnected. Maybe I have misinterpreted. Similar story for \$R_{13}\$. (more) |
— | over 1 year ago |
| Comment | Post #287232 |
OK cheers. I thought afterwards it must be. (more) |
— | over 1 year ago |
| Comment | Post #287232 |
OK I understand R23 and R13 now. Just k I didn't follow. (more) |
— | over 1 year ago |
| Comment | Post #287232 |
There are no mainline on stream calculators that get it right except 1 (mine). They all show daft maths that appears to have been copied from the originator to all the rest hence, why I did my own. In your answer, I'm not sure what R23 or R13 is meant to mean and ditto k. I appreciate the work but yo... (more) |
— | over 1 year ago |
| Comment | Post #287197 |
R1 + R3//(R2 + RL) = Rin in mathjax is \$R_1 + R_3 || (R_2 + R_L) = R_{IN}\$ = `\$R_1 + R_3 || (R_2 + R_L)= R_{IN}\$`. Thanks for trying Olin
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— | over 1 year ago |
| Comment | Post #287196 |
Yes, both are connected and both must see their respective impedances when they look into the taper-pad port (no tricks etc.). I'm probably going to post another unrelated question to give the site a boost. Maybe you should think about posting the odd question (that you can answer) given you are site... (more) |
— | over 1 year ago |
| Edit | Post #287196 |
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| Edit | Post #287196 |
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| Edit | Post #287196 |
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| Edit | Post #287196 |
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| Edit | Post #287196 |
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| Edit | Post #287196 | Initial revision | — | over 1 year ago |
| Question | — |
Deriving resistor values for a taper pad attenuator A taper pad is a resistive attenuator that maintains impedances on both ports and provides a specific amount of gain-loss (\$A{12}\$): - Image alt text I have derived formulas for each resistor (that I know to be correct) and have checked with micro-cap using DC analysis: - Image alt text ... (more) |
— | over 1 year ago |
| Comment | Post #286988 |
It's basically homework with no attempt to solve (more) |
— | over 1 year ago |
| Edit | Post #286945 |
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— | over 1 year ago |
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