Activity for Andy aka
Type | On... | Excerpt | Status | Date |
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Comment | Post #288153 |
Your upper picture of the phasors shows \$I_2\$ and \$I'_2\$ <-- they don't appear in the equivalent circuit shown below. Consistency is needed to give an answer. Neither do the loads (if I read the phasor diagrams correctly), match truly capacitive or truly inductive loads. The resistive load scenar... (more) |
— | over 1 year ago |
Edit | Post #288115 |
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— | over 1 year ago |
Edit | Post #288115 | Initial revision | — | over 1 year ago |
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A: Role of C2 (bypass capacitor) > Is C2 here to protect the voltage source from thermal noise? There's absolutely no chance that any level of thermal noise produced by a resistor will be sufficient to cause any reasonably designed power supply (voltage source) any problems whatsoever. Even badly designed power supplies will c... (more) |
— | over 1 year ago |
Edit | Post #288093 |
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— | over 1 year ago |
Edit | Post #288093 | Initial revision | — | over 1 year ago |
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A: DC offset correction loop (DC servo loop). What's its advantage, compared to a high-pass RC filter? > What are the advantages of such DC offset removal loop, compared to an RC high-pass filter? The primary advantage is that it keeps the front-end amplifier output centred in its DC operating region. If you used an external RC filter after the front-end amplifier and, sufficient offsets develop... (more) |
— | over 1 year ago |
Comment | Post #288027 |
A CDCS is an ideal component. A current mirror is a real circuit with real flaws and errors. (more) |
— | over 1 year ago |
Edit | Post #287956 |
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— | over 1 year ago |
Edit | Post #287956 |
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— | over 1 year ago |
Edit | Post #287956 | Initial revision | — | over 1 year ago |
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A: What does it mean for a signal to have impedance? > What does it mean for signals to have impedance? I expect that what it means is that a particular signal source has an effective series resistance (for a voltage source) or, an effective parallel resistance for a current source. Typically, a signal generator might have an output impedance ... (more) |
— | over 1 year ago |
Comment | Post #287801 |
I'm not buying it. Anyone who gets deleted should have their questions closed to prevent further new answers or comments and thus benefit the original (but now deleted) user. If you want to keep them as records in the question list (as per other closed questions) then so be it but, closing is needed... (more) |
— | almost 2 years ago |
Comment | Post #287801 |
In "another place", when this happens, the question gets locked pretty immediately when a fake ID is reported. [This one](https://electronics.stackexchange.com/questions/651563/can-a-50mm2-cable-handle-350-amps) was locked within 20 minutes of the question being flagged. Olin, you have the ability to... (more) |
— | almost 2 years ago |
Edit | Post #287788 |
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— | almost 2 years ago |
Edit | Post #287788 |
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— | almost 2 years ago |
Edit | Post #287788 | Initial revision | — | almost 2 years ago |
Question | — |
Should a fake user's posts be deleted if the fake user has subsequently been deleted by the site The question below was raised by a "new user". The identity of the "new user" was deleted because it was found to be an alias of an already suspended user: - Image alt text So, why is the question still active? It's a fake user created by a suspended user!! Shouldn't the question be "locked"... (more) |
— | almost 2 years ago |
Comment | Post #287746 |
Draw a schematic of what you tried. How did you measure 350 amperes? This sort of current requires very specialized equipment and power supplies. Maybe you meant 350 mA? (more) |
— | almost 2 years ago |
Comment | Post #287728 |
That is NOT the circuit you posted initially. How can you expect decent help when you post half a circuit? What Olin said about your original circuit being a mess is very true. (more) |
— | almost 2 years ago |
Comment | Post #287726 |
Except for the very useful case of the flyback converter!! (more) |
— | almost 2 years ago |
Comment | Post #287678 |
The AD9850 module is eveywhere on google: https://www.google.com/search?q=ad9850&rlz=1C1ONGR_en-GBGB999GB999&oq=AD9850&aqs=chrome.0.0i512l10.1043j0j15&sourceid=chrome&ie=UTF-8 (more) |
— | almost 2 years ago |
Edit | Post #287628 | Initial revision | — | almost 2 years ago |
Answer | — |
A: How to check realistic specs of small solar panel? All good designs and design testing is based on information contained in the component data sheets. A solar panel is no different so, you need to establish the operating conditions for measuring voltage and current based on the information provided by the supplier of the product. It's quite likely... (more) |
— | almost 2 years ago |
Comment | Post #287532 |
There is no formula because what you expect to happen actually does not happen. (more) |
— | almost 2 years ago |
Edit | Post #287537 | Initial revision | — | almost 2 years ago |
Answer | — |
A: How to calculate the voltage of a coil? The magnetic field will always be strongest in the middle of the solenoid. It will be slightly less at the ends of the solenoid and, it will be a lower value on the outside of the coil half way between the ends of the solenoid. In other words, no amount of voltage present on the coil will change ... (more) |
— | almost 2 years ago |
Comment | Post #287532 |
What, you want examples of crucibles so that you can make your coil? (more) |
— | almost 2 years ago |
Comment | Post #287480 |
You say radiation in your title but, you mention cables in the body of your question so, which is it; RF radiated emissions or cable-conducted emissions? (more) |
— | almost 2 years ago |
Comment | Post #287434 |
You said "voltage 18v" but your circuit shows 5 volts. You need to explain what you mean. (more) |
— | about 2 years ago |
Comment | Post #287302 |
The whole basis of this question is something apparently misunderstood in college and, is unable to be confirmed by Miss Mulan. It should now be closed. (more) |
— | about 2 years ago |
Comment | Post #287302 |
Your first assertion about S needs to be linked to where you read that. The information in your text book needs to be shown as a picture so it can be double checked. (more) |
— | about 2 years ago |
Edit | Post #287296 |
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— | about 2 years ago |
Edit | Post #287296 |
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— | about 2 years ago |
Edit | Post #287296 | Initial revision | — | about 2 years ago |
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A: Energy harvesting from non-invasive current sense transformer Most of the energy produced by the CT windings is being wasted in the internal burden resistor. See this data sheet to see what I mean. I calculate that it has a 60 Ω burden resistor and, at full primary current (30 amps) it wastes nearly 17 mW of power. At 3 amps, it wastes only 167 μW. ... (more) |
— | about 2 years ago |
Edit | Post #287257 |
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— | about 2 years ago |
Edit | Post #287257 |
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— | about 2 years ago |
Comment | Post #287257 |
I have no idea why you made this comment Tony. (more) |
— | about 2 years ago |
Edit | Post #287263 |
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— | about 2 years ago |
Edit | Post #287263 |
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— | about 2 years ago |
Edit | Post #287263 |
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— | about 2 years ago |
Edit | Post #287263 |
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— | about 2 years ago |
Edit | Post #287263 |
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— | about 2 years ago |
Edit | Post #287263 | Initial revision | — | about 2 years ago |
Answer | — |
A: Ceramic filter vs ceramic resonator The Murata part you have chosen as a replacement is unsuitable. Its only application is to cheaply replace crystals in oscillators and, as such, it will have a profoundly tight bandwidth (maybe less than 100 Hz or so) whereas the original filter you linked has a 20 dB bandwidth of 750 kHz (as per the... (more) |
— | about 2 years ago |
Comment | Post #287262 |
Try directly connecting the lines without any hinderance and see what the result is. Proceed with that situation until its fixed then, move onto coupling via the power rails. (more) |
— | about 2 years ago |
Comment | Post #287262 |
Try a direct communication to rule out DC filters affecting the comms. (more) |
— | about 2 years ago |
Comment | Post #287262 |
Data sheet links needed for the ceramic parts. Circuit diagram of the low pass-filters on the DC bus needed. Have you tried connecting two units directly to see that they work on an exclusive connection? (more) |
— | about 2 years ago |
Edit | Post #287257 |
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— | about 2 years ago |